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    <p>This is copied+edited from Stephen C's answer. Feel free to use:</p> <pre><code>public class Pair&lt;T1, T2&gt; { private final T1 v1; private final T2 v2; Pair(T1 v1, T2 v2) { this.v1 = v1; this.v2 = v2; } public T1 first(){ return v1; } public T2 second(){ return v2; } } public class ParallelIterator &lt;T1, T2&gt; implements Iterator&lt;Pair&lt;T1, T2&gt;&gt; { private final Iterator&lt;T1&gt; it1; private final Iterator&lt;T2&gt; it2; public ParallelIterator(Iterator&lt;T1&gt; it1, Iterator&lt;T2&gt; it2) { this.it1 = it1; this.it2 = it2; } @Override public boolean hasNext() { return it1.hasNext() &amp;&amp; it2.hasNext(); } @Override public Pair&lt;T1, T2&gt; next() { return new Pair&lt;T1, T2&gt;(it1.next(), it2.next()); } @Override public void remove(){ it1.remove(); it2.remove(); } } public class IterablePair &lt;T1, T2&gt; implements Iterable&lt;Pair&lt;T1,T2&gt;&gt; { private final List&lt;T1&gt; first; private final List&lt;T2&gt; second; public IterablePair(List&lt;T1&gt; first, List&lt;T2&gt; second) { this.first = first; this.second = second; } @Override public Iterator&lt;Pair&lt;T1, T2&gt;&gt; iterator(){ return new ParallelIterator&lt;T1,T2&gt;( first.iterator(), second.iterator() ); } } void someFunction(){ IterablePair&lt;X,Y&gt; listPair = new IterablePair&lt;X,Y&gt;( x, y ); for( Pair&lt;X,Y&gt; pair : listPair ){ X x = pair.first(); ... } } </code></pre> <p>This stops as soon as either list is out of elements, so you might want to check lists have equal size before creating an IterablePair.</p>
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