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    <p>Placing them in a <code>namespace</code> is an option. I don't see the need for a class. An instance of a class is mean to represent a state, but you're describing a bunch of free functions, so a stateless system.</p> <p>"It is not worth of wraping every function into single class." - this is not a valid argument for making the decision not to write a class. A class can have a single member and a single method, but if there is logic behind it, you should write it.</p> <p>If your functions and your logic mandates the use of a class, where your functions have the same logic but operate differently depending on the object, by all means, write a class. If your sole purpose is to group the functions together, when their logic doesn't really rely on the same instance of a class, group them in a namespace. </p> <p>An example based on your question:</p> <pre><code>namespace NetworkHelpers { //free function, use a namespace bool pingServer(std::string hostname); } //alternative, where the object has a state: class ServerConnection { std::string _hostname; public: NetworkHelpersClass(std::string hostname) { _hostname = hostname; } bool pingServer() { return NetworkHelpersNamespace::pingServer(_hostname); } }; </code></pre> <p>As you can see, inside the namespace, the function doesn't depend on anything other than the parameter.</p> <p>Inside the class, since it has a state and you create an object for each server (so similar behavior, yet different depending on the object), you call the function with no parameters as the object has a state.</p> <p>I hope this makes it clear.</p>
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    1. POBest practice of handling many single functions
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    1. USLuchian Grigore
    1. USLuchian Grigore
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    1. COWhere by "function" you mean "class"? :)
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    2. CO@themel, yes, I edited my answer just as soon as I hit the post button. :)
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    3. COI would add a further note: when it comes to choosing the namespace, it's a good habit to put the function in the same namespace (not `std`) as one of its arguments (choice to be made here, obviously). If it does not take any argument that lives in a namespace (except from `std`), then consider the namespace of its return type. If there is no namespace invovled at all... then create one.
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      1. USMatthieu M.
 

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