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    <p>You <strong>can't</strong> use <code>super</code> to call a method of <code>Navigation</code> from inside <code>EdumateSuperClass</code>.</p> <p><code>EdumateSuperClass</code> is the superclass of <code>Navigation</code>.</p> <p>Your hierarchy is: <code>ScriptSuperClass</code> -> <code>EdumateSuperClass</code> -> <code>Navigation</code>, where -> indicates "base class of" or "super class of".</p> <p><code>Navigation</code> can use <code>super.X()</code> to call <em>concrete</em> methods of <code>EdumateSuperClass</code>, <strong>not</strong> vice versa.</p> <p><br/> When you're doing <code>super.clickNewButton()</code> from inside <code>EdumateSuperClass</code>, it's trying to call the method <code>clickNewButton</code> from inside of the base class <code>ScriptSuperClass</code>. This method is <em>undefined</em> for the class <code>ScriptSuperClass</code> and therefore that is why you get that specific error.</p> <p><br/> <strong>EDIT:</strong> If you wanted, you could have <code>EdumateSuperClass</code> remain an abstract class which declares an abstract method <code>abstractMethod()</code> and <code>Navigation</code> be a concrete class that defines a concrete implementation of this method.</p> <p>You still <strong>can't</strong> use <code>super</code> from <code>EdumateSuperClass</code> to call this method inside <code>Navigation</code>, however this will allow you to use <code>EdumateSuperClass</code> as basically an interface when grouping objects.</p> <p>ie. You could have an array of <code>EdumateSuperClass</code>, which means that this array can hold references of <em>concrete</em> class objects derived/extended from <code>EdumateSuperClass</code>. For these classes to be <em>concrete</em> they <em>must</em> define <code>abstractMethod()</code>. From there you can store <code>Navigation</code> objects in that array and call <code>abstractMethod()</code> from any element in that array.</p> <p>However, that doesn't mean you're calling <code>abstractMethod()</code> from inside <code>EdumateSuperClass</code>, it'll still be a <code>Navigation</code> object that will contain the definition of <code>abstractMethod()</code> and be calling that from itself. I don't know if that makes it any clearer or not.</p> <p>Read up on <a href="http://download.oracle.com/javase/tutorial/java/IandI/polymorphism.html" rel="nofollow">polymorphism</a>.</p>
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    1. POHow to access a method from extending class in extended class?
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    1. COBy doing `super.clickNewButton();` I was just trying a suggestion from @xthexder
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    2. COGreat explanation, I needed something like that. What about the original question?
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    3. CO@Radek I editted my post based on what I now think you might be asking. You can use `EdumateSuperClass` as the type of an array and group objects derived from `EdumateSuperClass`, such as `Navigation` objects, and call a method that `EdumateSuperClass` *declares* as abstract and `Navigation` *defines*. But in the end `EdumateSuperClass` still knows nothing about its subclasses, the same way `Object` knows nothing about any of its derived classes. This is known as polymorphism.
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