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    <blockquote> <p>The program will not work properly because at Line 1, when the user presses Enter, it will leave in the input buffer 2 character: Enter key (ASCII code 13) and \n (ASCII code 10). Therefore, at Line 2, it will read the \n and will not wait for the user to enter a character.</p> </blockquote> <p>The behavior you see at line 2 is correct, but that's not quite the correct explanation. With text-mode streams, it doesn't matter what line-endings your platform uses (whether carriage return (0x0D) + linefeed (0x0A), a bare CR, or a bare LF). The C runtime library will take care of that for you: your program will see just <code>'\n'</code> for newlines.</p> <p>If you typed a character and pressed enter, then that input character would be read by line 1, and then <code>'\n'</code> would be read by line 2. See <a href="http://c-faq.com/stdio/scanfc.html" rel="noreferrer">I'm using <code>scanf %c</code> to read a Y/N response, but later input gets skipped.</a> from the comp.lang.c FAQ.</p> <p>As for the proposed solutions, see (again from the comp.lang.c FAQ):</p> <ul> <li><a href="http://c-faq.com/stdio/stdinflush.html" rel="noreferrer">How can I flush pending input so that a user's typeahead isn't read at the next prompt? Will <code>fflush(stdin)</code> work? </a></li> <li><a href="http://c-faq.com/stdio/stdinflush2.html" rel="noreferrer">If <code>fflush</code> won't work, what can I use to flush input?</a></li> </ul> <p>which basically state that the only portable approach is to do:</p> <pre><code>while ((c = getchar()) != '\n' &amp;&amp; c != EOF) { } </code></pre> <p>Your <code>getchar() != '\n'</code> loop works because once you call <code>getchar()</code>, the returned character already has been removed from the input stream.</p> <p>Also, I feel obligated to discourage you from using <code>scanf</code> entirely: <a href="http://c-faq.com/stdio/scanfprobs.html" rel="noreferrer">Why does everyone say not to use <code>scanf</code>? What should I use instead?</a> </p>
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