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PO
primarykey
Id
78537
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
1
CommunityOwnedDate
CreationDate
2008-09-17T00:06:37.890
FavoriteCount
0
LastActivityDate
2008-09-18T12:13:37.573
LastEditDate
2008-09-18T12:13:37.573
LastEditorUserId
6970
OwnerUserId
6970
ParentId
76581
PostTypeId
2
Score
2
ViewCount
0
LastEditorDisplayName
Mike Dimmick
text
Body
It may be that it just doesn't like the very short keys you're using. I found <a href="http://msdn.microsoft.com/en-us/library/aa381969.aspx" rel="nofollow noreferrer">the desktop version of that article</a> which may help, as it has a full example. EDIT: The OP realised from the example that you have to tell CryptGenKey how long the keys are, which you do by setting the top 16-bits of the flags to the number of bits you want to use. If you leave this as 0, you get the default key length. This is documented in the Remarks section of the device documentation, and with the dwFlags parameter in the <a href="http://msdn.microsoft.com/en-us/library/aa379941(VS.85).aspx" rel="nofollow noreferrer">desktop documentation</a>. For the Diffie-Hellman key-exchange algorithm, the Base provider defaults to 512-bit keys and the Enhanced provider (which is the default) defaults to 1024-bit keys, on Windows XP and later. There doesn't seem to be any documentation for the default lengths on CE. The code should therefore be: <pre><code>BYTE p[64] = { 139 }; // little-endian, all other bytes set to 0 BYTE g[64] = { 5 }; CRYPT_DATA_BLOB pblob; pblob.cbData = sizeof( p); pblob.pbData = p; CRYPT_DATA_BLOB gblob; gblob.cbData = sizeof( g ); gblob.pbData = g; HCRYPTKEY hKey; if ( ::CryptGenKey( m_hCryptoProvider, CALG_DH_SF, ( 512 << 16 ) | CRYPT_PREGEN, &hKey ) ) { ::CryptSetKeyParam( hKey, KP_P, ( LPBYTE ) &pblob, 0 ); </code></pre>
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1. POI have P & G-- how do I use the Wincrypt API to generate a Diffie-Hellman keypair?
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1. USMike Dimmick
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1. USMike Dimmick
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1. POI have P & G-- how do I use the Wincrypt API to generate a Diffie-Hellman keypair?
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1. COThanks, Mike-- I found (from your reference) that it was *two* things. You have to tell CryptGenKey the key length by or'ing the length in bits, left shifted by 16, into the flags parameter (undocumented, of course, you have to read the sample). *Also*, the key length must be at least 512 bits.
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