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    <p>On the same lines as JSON.encode is to use join().</p> <pre><code>function checkArrays( arrA, arrB ){ //check if lengths are different if(arrA.length !== arrB.length) return false; //slice so we do not effect the original //sort makes sure they are in order //join makes it a string so we can do a string compare var cA = arrA.slice().sort().join(","); var cB = arrB.slice().sort().join(","); return cA===cB; } var a = [1,2,3,4,5]; var b = [5,4,3,2,1]; var c = [1,2,3,4]; var d = [1,2,3,4,6]; var e = ["1","2","3","4","5"]; //will return true console.log( checkArrays(a,b) ); //true console.log( checkArrays(a,c) ); //false console.log( checkArrays(a,d) ); //false console.log( checkArrays(a,e) ); //true </code></pre> <p>Only problem is if you care about types which the last comparison tests. If you care about types, you will have to loop.</p> <pre><code>function checkArrays( arrA, arrB ){ //check if lengths are different if(arrA.length !== arrB.length) return false; //slice so we do not effect the orginal //sort makes sure they are in order var cA = arrA.slice().sort(); var cB = arrB.slice().sort(); for(var i=0;i&lt;cA.length;i++){ if(cA[i]!==cB[i]) return false; } return true; } var a = [1,2,3,4,5]; var b = [5,4,3,2,1]; var c = [1,2,3,4]; var d = [1,2,3,4,6]; var e = ["1","2","3","4","5"]; console.log( checkArrays(a,b) ); //true console.log( checkArrays(a,c) ); //false console.log( checkArrays(a,d) ); //false console.log( checkArrays(a,e) ); //false </code></pre> <p>If the order should remain the same, than it is just a loop, no sort is needed.</p> <pre><code>function checkArrays( arrA, arrB ){ //check if lengths are different if(arrA.length !== arrB.length) return false; for(var i=0;i&lt;arrA.length;i++){ if(arrA[i]!==arrB[i]) return false; } return true; } var a = [1,2,3,4,5]; var b = [5,4,3,2,1]; var c = [1,2,3,4]; var d = [1,2,3,4,6]; var e = ["1","2","3","4","5"]; console.log( checkArrays(a,a) ); //true console.log( checkArrays(a,b) ); //false console.log( checkArrays(a,c) ); //false console.log( checkArrays(a,d) ); //false console.log( checkArrays(a,e) ); //false </code></pre>
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    1. POHow to compare arrays in JavaScript?
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    1. COThanks, @epascarello, in my specific case, I am only comparing the order of elements, not types, so `.join();` would work as well. Thanks for the insight.
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      1. USJulian H. Lam
    2. COWith your first version of `checkArrays()`: `checkArrays([11,22,33,44], [1,12,23,344]) // true`
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    3. COwhoops, should be joined with a separator. :)
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