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POget the selected index value of <select> tag in php
 

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    <p>I was trying to get the selected value from the <code>&lt;select&gt;</code> tag in PHP, but I get errors. </p> <p>These is what I have done,</p> <p>HTML</p> <pre><code>&lt;select name="gender"&gt; &lt;option value="select"&gt; Select &lt;/option&gt; &lt;option value="male"&gt; Male &lt;/option&gt; &lt;option value="female"&gt; Female &lt;/option&gt; &lt;/select&gt; </code></pre> <p>PHP script</p> <pre><code>$Gender = $_POST["gender"]; </code></pre> <p>but i get these error</p> <pre><code>Notice: Undefined index: gender in C:\xampp\htdocs\omnama\signup.php on line 7 </code></pre> <p>php script</p> <pre><code>$Gender = isset($_POST["gender"]); ' it returns a empty string ? why ? </code></pre> <p>HTML </p> <pre><code>&lt;form name="signup_form" action="./signup.php" onsubmit="return validateForm()" method="post"&gt; &lt;table&gt; &lt;tr&gt; &lt;td&gt; First Name &lt;/td&gt;&lt;td&gt; &lt;input type="text" name="fname" size=10/&gt;&lt;/td&gt;&lt;/tr&gt; &lt;tr&gt; &lt;td&gt; Last Name &lt;/td&gt;&lt;td&gt; &lt;input type="text" name="lname" size=10/&gt;&lt;/td&gt;&lt;/tr&gt; &lt;tr&gt; &lt;td&gt; Your Email &lt;/td&gt;&lt;td&gt; &lt;input type="text" name="email" size=10/&gt;&lt;/td&gt;&lt;/tr&gt; &lt;tr&gt; &lt;td&gt; Re-type Email &lt;/td&gt;&lt;td&gt; &lt;input type="text" name="remail"size=10/&gt;&lt;/td&gt;&lt;/tr&gt; &lt;tr&gt; &lt;td&gt; Password &lt;/td&gt;&lt;td&gt; &lt;input type="password" name="paswod" size=10/&gt; &lt;/td&gt;&lt;/tr&gt; &lt;tr&gt; &lt;td&gt; Gender &lt;/td&gt;&lt;td&gt; &lt;select name="gender"&gt; &lt;option&gt; Select &lt;/option&gt; &lt;option value="male"&gt; Male &lt;/option&gt; &lt;option value="female"&gt; Female &lt;/option&gt;&lt;/select&gt;&lt;/td&gt;&lt;/tr&gt; &lt;tr&gt; &lt;td&gt; &lt;input type="submit" value="Sign up" id="signup"/&gt; &lt;/td&gt; &lt;/tr&gt; &lt;/table&gt; &lt;/form&gt; </code></pre> <p>This is my php script</p> <pre><code> &lt;?php $con = mysql_connect("localhost","root",""); $fname = $_POST["fname"]; $lname = $_POST["lname"]; $email = $_POST["email"]; $paswod = $_POST["paswod"]; $Gender = $_POST["gender"]; mysql_select_db("homepage"); if(mysql_num_rows(mysql_query("SELECT Email FROM users WHERE Email = '$email'",$con))) { echo "userid is already there"; } else { $sql= "INSERT INTO users (FirstName, LastName,Email,Password,Gender) VALUES ('$fname','$lname','$email','$paswod','$Gender')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "created"; } ?&gt; </code></pre> <p>Please help me with these. I have to get the selected index value in the PHP. </p> <p>I have read this <a href="http://www.dreamincode.net/forums/topic/48477-how-to-get-the-select-value-from-the-drop-down-list/" rel="nofollow noreferrer">link</a> to use <code>&lt;select&gt;</code> tag in PHP. </p>
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    1. CO`$Gender = isset($_POST["gender"]); ' it returns a null string ? why ?` --- this code **cannot** return `null`, by definition
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    2. COnull ! there i mean when i open and see mysql i see an empty string in the database!
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    3. COIs your form a valid form? Mean, between the `<form></form>` tags and with a submit button
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