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    <p>If I understood you right, you could do it this way:</p> <pre><code>a = 0b0010111010 '{:010b}'.format(a) #The output is: '0010111010' </code></pre> <p><em>Python 2.7</em></p> <p>It uses string <a href="http://docs.python.org/release/2.7/library/string.html#format-specification-mini-language" rel="nofollow"><code>format</code> method</a>.</p> <p>This is the answer if you want to represent the binary string with leading zeros.</p> <p>If you are just trying to generate a random string with a binary you could do it this way:</p> <pre><code>from random import choice ''.join(choice(('0','1')) for _ in range(10)) </code></pre> <h1>Update</h1> <p>Unswering your update. I made a code which has a different output if compared to yours:</p> <pre><code>from random import choice from pprint import pprint arr = [] def create_string(x): for i in xrange(10): # 10 random populations arr.append([]) for j in xrange(x): # population size v = ''.join(choice(('0','1')) for _ in range(10)) arr[-1].append(v) return arr a = create_string(5) pprint(a) </code></pre> <p>The output is:</p> <pre><code>[['1011010000', '1001000010', '0110101100', '0101110111', '1101001001'], ['0010000011', '1010011101', '1000110001', '0111101011', '1100001111'], ['0011110011', '0010101101', '0000000100', '1000010010', '1101001000'], ['1110101111', '1011111001', '0101100110', '0100100111', '1010010011'], ['0100010100', '0001110110', '1110111110', '0111110000', '0000001010'], ['1011001011', '0011101111', '1100110011', '1100011001', '1010100011'], ['0110011011', '0001001001', '1111010101', '1110010010', '0100011000'], ['1010011000', '0010111110', '0011101100', '1111011010', '1011101110'], ['1110110011', '1110111100', '0011000101', '1100000000', '0100010001'], ['0100001110', '1011000111', '0101110100', '0011100111', '1110110010']] </code></pre> <p>Is this what you are looking for?</p>
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    1. COYes, thank you.
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    2. CO@espais You are welcome!
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