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    <p>If you mean just the syntax then this regexp should work for you</p> <pre><code>import re ... if re.match("[0-9a-f]{2}([-:]?)[0-9a-f]{2}(\\1[0-9a-f]{2}){4}$", x.lower()): ... </code></pre> <p>it accepts 12 hex digits with either <code>:</code> or <code>-</code> or nothing as separators between pairs (but the separator must be uniform... either all separators are <code>:</code> or are all <code>-</code> or there is no separator).</p> <p>This is the explanation:</p> <ul> <li><code>[0-9a-f]</code> means an hexadecimal digit</li> <li><code>{2}</code> means that we want two of them</li> <li><code>[-:]?</code> means either a dash or a colon but optional. Note that the dash as <strong>first</strong> char doesn't mean a range but only means itself. This subexpression is enclosed in parenthesis so it can be reused later as a back reference.</li> <li><code>[0-9a-f]{2}</code> is another pair of hexadecimal digits</li> <li><code>\\1</code> this means that we want to match the same expression that we matched before as separator. This is what guarantees uniformity. Note that the regexp syntax is <code>\1</code> but I'm using a regular string so backslash must be escaped by doubling it.</li> <li><code>[0-9a-f]{2}</code> another pair of hex digits</li> <li><code>{4}</code> the previous parenthesized block must be repeated exactly 4 times, giving a total of 6 pairs of digits: <code>&lt;pair&gt; &lt;sep&gt; &lt;pair&gt; ( &lt;same-sep&gt; &lt;pair&gt; ) * 4</code></li> <li><code>$</code> The string must end right after them</li> </ul> <p>Note that in Python <code>re.match</code> only checks starting at the start of the string and therefore a <code>^</code> at the beginning is not needed.</p>
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    1. POHow do I validate the format of a MAC address?
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    1. CODon't forget a `$` at the end of the regular expression. Otherwise it'll match `'00:29:15:80:4E:4A:any random text here'` as well.
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    2. CO@PetrViktorin: Good point. fixed.
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