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POany way to make a progress bar that when the value is 0, it's 100%?
 

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  1. POany way to make a progress bar that when the value is 0, it's 100%?
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    <p>I'm working on a debt tracking app, and have need for a progress bar that as the current debt goes down, the progress goes up. The only way I can think to do this would be to fudge the numbers around so that the progress bar MAX is set to 0, and then change the starting debt to be a negitive number, as follows</p> <pre><code>ProgressBar.setMax(0); Integer startingdebt = -1000; // 1000$ owed ProgressBar.setProgress(currentlyowed); //say, -500 </code></pre> <p>so you start with -1000, and add 500$ to it if you paid it. I don't know if this would work though, because I'm sure the progressbar control has a set minimum of 0 already, so you can't set max the same...is there a way to do this?</p> <p><strong>Edit:</strong> Thanks for the answers guys, but I found an easier way: to share with others, here's my final code block:</p> <pre><code> double startingamount = (this.c.getDouble(this.c.getColumnIndex(DbAdapter.KEY_STARTINGAMOUNT))); double currentamount = (this.c.getDouble(this.c.getColumnIndex(DbAdapter.KEY_CURRENTAMOUNT))); currentdebt.setText(formatter.format(currentamount)); double progresspaid = new Double(startingamount-currentamount); double progresspercentage = new Double((progresspaid / startingamount)*100); int progresspercent = (int)progresspercentage; progressbar.setText(Integer.toString(progresspercent)+"%"); progressbar.setMax(100); progressbar.setProgress(progresspercent); </code></pre> <p>the key was to get a variable that subtracts the current amount from the starting amount, and then divides that by the starting amount.</p> <pre><code>double progresspaid = new Double(startingamount-currentamount); double progresspercentage = new Double((progresspaid / startingamount)*100); </code></pre> <p>Thanks again though, I really appreciate people helping me learn Java and android development, I'm a VB.net developer so some of this is still foreign to me.</p>
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