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POParse Apache log in PHP using preg_match
 

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  1. POParse Apache log in PHP using preg_match
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    <p>I need to save data in a table (for reporting, stats etc...) so a user can search by time, user agent etc. I have a script that runs every day that reads the Apache Log and then insert it in the database. </p> <p>Log format:</p> <pre><code>10.1.1.150 - - [29/September/2011:14:21:49 -0400] "GET /info/ HTTP/1.1" 200 9955 "http://www.domain.com/download/" "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_8; de-at) AppleWebKit/533.21.1 (KHTML, like Gecko) Version/5.0.5 Safari/533.21.1" </code></pre> <p>My regex:</p> <pre><code>preg_match('/^(\S+) (\S+) (\S+) \[([^:]+):(\d+:\d+:\d+) ([^\]]+)\] \"(\S+) (.*?) (\S+)\" (\S+) (\S+) (\".*?\") (\".*?\")$/',$log, $matches); </code></pre> <p>Now when I print: </p> <pre><code>print_r($matches); Array ( [0] =&gt; 10.1.1.150 - - [29/September/2011:14:21:49 -0400] "GET /info/ HTTP/1.1" 200 9955 "http://www.domain.com/download/" "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_8; de-at) AppleWebKit/533.21.1 (KHTML, like Gecko) Version/5.0.5 Safari/533.21.1" [1] =&gt; 10.1.1.150 [2] =&gt; - [3] =&gt; - [4] =&gt; 29/September/2011 [5] =&gt; 14:21:49 [6] =&gt; -0400 [7] =&gt; GET [8] =&gt; /info/ [9] =&gt; HTTP/1.1 [10] =&gt; 200 [11] =&gt; 9955 [12] =&gt; "http://www.domain.com/download/" [13] =&gt; "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_8; de-at) AppleWebKit/533.21.1 (KHTML, like Gecko) Version/5.0.5 Safari/533.21.1" ) </code></pre> <p>I get: <code>"http://www.domain.com/download/"</code> and same for user agent. How can I get rid of these <code>"</code> in the regex? Bonus (Is there any quick way to insert the date/time easily)?</p> <p>Thanks</p>
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    1. USTech4Wilco
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    1. COThis is a duplicate of question #2221636
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      1. USDaniel S. Sterling
    2. COI've written a simple helper class for this. See https://github.com/Spudley/ApacheLogIterator
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