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    <p>From what I understand, you want to get all arrays in new_dataArray that are not in old_dataArray and I'm assuming that if the first element in each (the 'id-n' element) is the same, then so is the rest of the array. You can do so like this:</p> <pre><code>// create an array to store our results: var results = new Array(); // loop through new_dataArray: outerloop: for (var i = 0; i &lt; new_dataArray.length; ++i) { // loop through old_dataArray to compare the i'th element // in new_dataArray with each in old_dataArray: for (var j = 0; j &lt; old_dataArray.length; ++j) { // check if the ids are the same if (new_dataArray[i][0] == old_dataArray[j][0]) // yes it's there, so move on to the next element of new_dataArray continue outerloop; } // if we get here, continue outerloop; was never called so // this element is not in old_dataArray results.push(new_dataArray[i]); } // now results contains all arrays that are in new_dataArray // but not in old_dataArray </code></pre> <p>EDIT: If, however, you want ALL the elements in each array to be equal, not just the first (id-n) element, use this:</p> <pre><code>// create an array to store our results: var results = new Array(); // loop through new_dataArray: outerloop: for (var i = 0; i &lt; new_dataArray.length; ++i) { // loop through old_dataArray to compare the i'th element // in new_dataArray with each in old_dataArray: innerloop: for (var j = 0; j &lt; old_dataArray.length; ++j) { // check if the arrays are the same size: if (new_dataArray[i].length != old_dataArray[j].length) // no, so they must be different continue innerloop; // check if the arrays have the same values for (var k = 0; k &lt; old_dataArray[j].length; ++k) { if (new_dataArray[i][k] != old_dataArray[j][k]) // the k'th element is different continue innerloop; } // if we get here, then we have found a match, so move on continue outerloop; } // if we get here, continue outerloop; was never called so // this element is not in old_dataArray results.push(new_dataArray[i]); } // now results contains all arrays that are in new_dataArray // but not in old_dataArray </code></pre>
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    1. POCompare multi dimentional arrays in javascript
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    1. CO+1 for the `continue outerloop`. (I know some people don't like labels and continues, but then I know some people so stuffy they wouldn't even break out of a non-nested loop; I _do_ like the `continue outerloop` syntax, especially with meaningful comments like yours.)
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    2. COThank you. I always try to minimise use of temporary variables and unnecessary conditional checks. Every clock-cycle counts!
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