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POHow do i pass a generator yield statement to another function. -Python
 

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  1. POHow do i pass a generator yield statement to another function. -Python
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    <p>i've been reading on this site and can't seem to find the specific answer i want. i've tried reading david beasly's slides on iteration and generators but still can't quite get the answer i'm looking for though the question seems simple. i'm running a clock-based simulation (Brian for neural networking) and i have a generator that is manipulating the outputs and adding them to a running sum (in order for there to be n exponential decay for a simple low-pass filter). i then want to take the outputs of these generators, at each time-step and then use them in another function to update some of the state variables, it says that since the item is of the generator type i cannot do this. code and explanation of code is as follows:</p> <pre><code>import numpy our_range=numpy.arange(0*ms,duration+defaultclock.dt,defaultclock.dt) a=our_range c=defaultclock.t #this is a clock that is part of the program i'm running, it updates every #timestep and runs through the range given above def sum_tau(neuron): #this gives a running sum which i want to access (the alphas can be ignored as they are problem specific) for c in a: #had to express it like this (with c and a) or it wouldn't run if c ==0: x=0 elif defaultclock.still_running()==False: return else: x = x*(1-alpha) + p(neuron)*alpha print x yield x #p(neuron) just takes some of the neurons variables and gives a number b=sum_tau(DN) #this is just to specify the neuron we're working on, problem specific @network_operation def x(): b.next() </code></pre> <p>the @network_operation means that every clock timestep the function below will be executed, therefore updating the sum to it's required value. Now what i want to do here is update a value that is used for the simulation (where d is the output to another generator, not shown, but very similar to b) by typing:</p> <pre><code>ron= (d/(1-b)) </code></pre> <p>However, it says i cannot use a generator object in this way, i have used print statements to determine that that b (and d) give the outputs i want every timestep (when the simulation is run) but I cannot seem to take these outputs and do anything with them. (more specifically unsupported operand type '-' for int and generator. i tried converting it to a number with float() but obviously this doesn't work for the same reason, i feel there must be a very simple solution to my problem but i can't seem to find it. Thanks in advance.</p>
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    1. USPeter Graham
    1. USMike H-R
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      1. POHow do i pass a generator yield statement to another function. -Python
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    1. CO`1-b` cannot work as `b` is a generator. You need to do `1-b.next()` or `value = b.next(); 1-value`.
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      1. POHow do i pass a generator yield statement to another function. -Python
      1. USSteven Rumbalski
    2. COPlease learn to use the shift key. "I" refers to yourself. It's important to spell correctly.
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      1. POHow do i pass a generator yield statement to another function. -Python
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    3. CO@StevenRumbalski Thanks Steven, this is indeed what I was looking for. unfortunately I now have a new problem as the network_operation decorator I need to use to apply this update step to the generator in sync with the simulation clock does not allow a return value (it show's up as "None") is there any way to return a value to the highest order namespace in order to get this value and not allow the generator to get out of sync with the simulation (so that in your notation I can pass the "value" up to the parent namespace and take it outside of the namespace of the decorator and function?
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      1. POHow do i pass a generator yield statement to another function. -Python
      1. USMike H-R
 

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