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POC++ Saving/Loading a function as bytes. Getting the size of a function
 

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    <p>Ok so I've used function pointers for some time. I was trying to figure out if this was possible.</p> <p>First. It IS possible to convert a function pointer into an array of bytes.</p> <p>It is also possible to reconstruct that function with the bytes in that array.</p> <p>I would like to save a function into an array of bytes, and lets say save it to a text file (func.dat). Then later read that text file and execute the particular function... Is it possible? It seems it should be possible the only problem I run across is finding the size of the array that makes up the function.</p> <p>Is there any way to do this?</p> <pre><code>int func() { return 1+1; } int main() { int (*foo)() = func; char* data = (char*)func; // write all the data char* copyFunc = new char[sizeof(func)]; for(int i = 0; i &lt; sizeof(func); i++) copyFunc[i] = data[i]; int (*constructedFoo)() = (int (*)())copyFunc; return 0; } </code></pre> <p>of course this code won't compile because sizeof does not work for functions, does anyone know how to get the size of a function? Or the size of the function header/footer.</p> <p>I have tried things like</p> <pre><code>int func() { 1+1; new char('}'); } </code></pre> <p>Then searched for the } char (as the end of the function) but that size doesn't work.</p> <p>If your wondering why I need it, it could be used for lets say, sending a function to a remote computer to execute (thinking of parallel processing) Or even saving a function in a file like in my first example to later be used, this can be helpful.</p> <p>Any help is greatly appreciated.</p>
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