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    <p>Change the <code>command</code> to:</p> <pre><code>lambda the_year=the_year: year_seter(the_year) </code></pre> <p>The problem has to do with how Python looks up the value of <code>the_year</code>. When you use</p> <pre><code>lambda : year_seter(the_year) </code></pre> <p><code>the_year</code> is not in the local scope of the lambda function, so Python goes looking for it in the <a href="https://stackoverflow.com/questions/291978/short-description-of-python-scoping-rules">extended, global, then builtin scopes</a>. It finds it in the global scope. The <code>for-loop</code> uses <code>the_year</code>, and after the for-loop ends, <code>the_year</code> retains its last value, 2011. Since the lambda function is executed after the for-loop has ended, the value Python assigns to <code>the_year</code> is 2011.</p> <p>In contrast, if you use a parameter with a default value, the default value is fixed at the time the function (lambda) is <strong>defined</strong>. Thus, each <code>lambda</code> gets a different value for <code>the_year</code> fixed as the default value.</p> <p>Now when the lambda is called, again Python goes looking for the value of <code>the_year</code>, but this time finds it in the lambda's local scope. It binds the default value to <code>the_year</code>.</p> <hr> <p>PS. </p> <ol> <li><p>You could also forgo defining <code>year_seter</code> and just do:</p> <pre><code>lambda the_year=the_year: year.set(the_year) </code></pre></li> <li><code>list_of_years = range(1995,2012)</code> also works.</li> </ol>
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    1. COWonderful answer and explanation. Thanks The year_seter and list_of_years have been presented here in simplified form.
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