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POTrouble with Recursion in Python
 

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  1. POTrouble with Recursion in Python
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    <p>Working with python 2.7.</p> <p>The following code allows me to input the winning percentage of two teams (WP_1 and WP_2) a number of wins (k) and determine given the two team's winning percentages, the probability that team one will have more wins at the end of the season (Playoff_Probability):</p> <pre><code>def PlayoffProb(WP_1, k, WP_2): TProb_2 = 0 p = float(WP_1)/1000 q = float(WP_2)/1000 n = 162.0 G = math.factorial(n)/(math.factorial(k)*math.factorial(n-k)) Prob = G*(p**k)*((1-p)**(n-k)) for c in range(0, k): G_2 = math.factorial(n)/(math.factorial(c)*math.factorial(n-c)) Prob_2 = G_2*(q**c)*(1-q)**(n-c) TProb_2 += Prob_2 Playoff_Probability = Prob*TProb_2 print Playoff_Probability print TProb_2 </code></pre> <p>But what would be a lot easier is if the function could be written recursively so that it would perform the same operation over every possible value of k and return the total probability of ending the season with more wins (which I believe should be given by the Playoff_Probability for each value run through the function of k, which I've tried to set equal to Total_Playoff_Probability).</p> <p>I've tried the following code, but I get a TypeError telling me that 'float' object is not callable at the return Total_Playoff_Probability step. I'm also not at all sure that I've set up the recursion appropriately.</p> <pre><code>def PlayoffProb2(WP_1, k, WP_2): TProb_2 = 0 Total_Playoff_Probability = 0 p = float(WP_1)/1000 q = float(WP_2)/1000 n = 162.0 G = math.factorial(n)/(math.factorial(k)*math.factorial(n-k)) Prob = G*(p**k)*((1-p)**(n-k)) for c in range(0, k): G_2 = math.factorial(n)/(math.factorial(c)*math.factorial(n-c)) Prob_2 = G_2*(q**c)*(1-q)**(n-c) TProb_2 += Prob_2 Playoff_Probability = Prob*TProb_2 Total_Playoff_Probability += Playoff_Probability if k == 162: return Total_Playoff_Probability else: return PlayoffProb2(WP_1, k+1, WP_2) </code></pre> <p>Any help would be greatly appreciated!</p>
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      1. USWinston Ewert
 

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