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POProblem with SQL with LEFT JOIN for a radius search
 

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  1. POProblem with SQL with LEFT JOIN for a radius search
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    <p>I'm having some problems with my radius search. I have a table with zip codes, place names and geographical coordinates (based on OpenGeoDB).</p> <p>Here is my SQL-Command:</p> <pre><code>SELECT main.zc_zip, (ACOS( SIN(RADIANS(main.zc_lat)) * SIN(RADIANS(geo.zc_lat)) + COS(RADIANS(main.zc_lat)) * COS(RADIANS(geo.zc_lat)) * COS(RADIANS(main.zc_lon) - RADIANS(geo.zc_lon)) ) * 6380) AS `distance` FROM tx_sdfilmbase_geodb main LEFT JOIN tx_sdfilmbase_geodb geo ON geo.zc_location_name LIKE '%frauenfeld%' WHERE (ACOS( SIN(RADIANS(main.zc_lat)) * SIN(RADIANS(geo.zc_lat)) + COS(RADIANS(main.zc_lat)) * COS(RADIANS(geo.zc_lat)) * COS(RADIANS(main.zc_lon) - RADIANS(geo.zc_lon)) ) * 6380) &lt; 20 AND main.disabled=0 ORDER BY `distance` ASC </code></pre> <p>I get results for all locations around Frauenfeld within a radius of 20 kilometres. However, I don't get any result for locations named "frauenfeld" - i.e. I get all surrounding places but not the searched placed itself.</p> <p>How do I have to change the SQL to also get the place itself? I tried different things, but always the same result...</p> <p>Would be glad for some hints.</p> <p>Greets Stefan</p> <p><strong>Edit to answer comments by ypercube and Matt Gibson:</strong></p> <p>All entries in the database table have disabled=0 at the moment. </p> <p>Amongst many others, I get the following results (zip, distance):</p> <ul> <li>8552 3.7661608052471</li> <li>8500 4.184731709915</li> <li>8523 4.9298917004071</li> <li>9548 4.9771821340396</li> </ul> <p>Zip codes for Frauenfeld: 8500, 8501, 8502 and 8503.</p> <p>Missing entries in the result would be (zip, distance):</p> <ul> <li>8500 0</li> <li>8501 0</li> <li>8502 0</li> <li>8503 0</li> </ul> <p>However, the data in the geo database is correct (zip, place, latitude, longitude):</p> <ul> <li>8503 Frauenfeld 47.557707 8.897367</li> <li>8502 Frauenfeld 47.557707 8.897367</li> <li>8501 Frauenfeld 47.557707 8.897367</li> <li>8500 Frauenfeld 47.557707 8.897367</li> </ul> <p><strong>Edit to reply to answer by kuru kuru pa:</strong></p> <p>Thanks for your reply!<br> The Answer looks like this now (zc_location_name, zc_zip, disabled, distance): </p> <pre><code>Frauenfeld 8500 0 NULL Frauenfeld 8503 0 NULL Frauenfeld 8502 0 NULL Frauenfeld 8501 0 NULL Gerlikon 8500 0 4.18473170991499 </code></pre> <p>Why is it NULL and not 0? Any guesses? :-) Btw: Each result was listed 4 times (I just posted each once).</p>
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    1. COHave you checked if the location with `name LIKE '%frauenfeld%'` has `disabled=0` ?
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      1. POProblem with SQL with LEFT JOIN for a radius search
      1. USypercubeᵀᴹ
    2. COCan you give us an example of the rows you think your query *should* be finding? Also, is that the right SQL? Your question title says LEFT JOIN, but you don't appear to be using a LEFT JOIN in the query.
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