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7327047
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2011-09-06T22:47:31.003
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<a href="http://www.parashift.com/c++-faq-lite/ctors.html#faq-10.14" rel="nofollow">http://www.parashift.com/c++-faq-lite/ctors.html#faq-10.14</a> <blockquote> The static initialization order fiasco is a very subtle and commonly misunderstood aspect of C++. Unfortunately it's very hard to detect — the errors often occur before main() begins. In short, suppose you have two static objects x and y which exist in separate source files, say x.cpp and y.cpp. Suppose further that the initialization for the y object (typically the y object's constructor) calls some method on the x object. That's it. It's that simple. The tragedy is that you have a 50%-50% chance of dying. If the compilation unit for x.cpp happens to get initialized first, all is well. But if the compilation unit for y.cpp get initialized first, then y's initialization will get run before x's initialization, and you're toast. E.g., y's constructor could call a method on the x object, yet the x object hasn't yet been constructed. </blockquote> The first method you listed avoids this problem completely. It's called the "construct on first use idiom" <blockquote> The downside of this approach is that the object is never destructed. There is another technique that answers this concern, but it needs to be used with care since it creates the possibility of another (equally nasty) problem. Note: The static initialization order fiasco can also, in some cases, apply to built-in/intrinsic types. </blockquote>
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1. POAbout two kinds of singleton pattern in C++
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1. USMooing Duck
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1. POAbout two kinds of singleton pattern in C++
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