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    <p>I see several minor problems in your code:</p> <ul> <li>If <code>varContainingNameOfSpecificFolder</code> contains characters that have a meaning in regular expressions (<code>.</code> being the most likely candidate), then you <strong>must</strong> use <code>Pattern.quote()</code> to quote that part.</li> <li>your use of <code>String.format()</code> is unnecessary, you can use simply <code>String</code> concatenation using <code>+</code> here, which is easier to read.</li> <li>you don't need the assignment to <code>myValue</code>, simply <code>return</code> the result of <code>substring</code></li> <li>the <code>substring</code> call is <em>unnecessary</em> here! Simply replacing that expression with <a href="http://download.oracle.com/javase/7/docs/api/java/util/regex/Matcher.html#group%28int%29" rel="nofollow"><code>matcher.group(1)</code></a> has the same effect!</li> <li>using <a href="http://download.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll%28java.lang.String,%20java.lang.String%29" rel="nofollow"><code>String.replaceAll()</code></a> might be a valid shortcut, but you'd have to modify your regex slightly.</li> </ul> <p>So my version would be:</p> <pre><code>public static String getValueThatIneed(String path) { String regex = ".*\\\\" + Pattern.quote(varContainingNameOfSpecificFolder) + "\\\\([0-9]+)\\\\.*"; String result = path.replaceAll(regex, "$1"); if (result.equals(path)) { throw new IllegalArgumentException("&lt;" + path + "&gt; does not contain the thin i need!"); } return result; } </code></pre> <p>If you don't care about error checking (as your code doesn't do it either) you can simply <em>return</em> the result of the <code>replaceAll()</code> method and have a two-line method:</p> <pre><code>public static String getValueThatIneed(String path) { String regex = ".*\\\\" + Pattern.quote(varContainingNameOfSpecificFolder) + "\\\\([0-9]+)\\\\.*"; return path.replaceAll(regex, "$1"); } </code></pre> <p>However, I <strong>strongly</strong> encourage you to keep it, as otherwise you can easily miss nasty bugs in your code.</p>
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    1. POdo i really need 4 lines of code to get a value from the middle of a string?
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    1. USJoachim Sauer
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    1. POdo i really need 4 lines of code to get a value from the middle of a string?
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    1. COcan you show an example of how to use String.replaceAll() for this task? thanks
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    2. CO@dan: i demonstrated it on my version, see the second code block.
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    3. COThanks. great answer. can you explain why in my version i don't need ".*" at the beginning and the end of the regex and it works with group(1), and in your version you added ".*" and witout it, it doesnt work with $1?
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