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    <p>Sure you can, you can build a similar example with any type of Vector:</p> <pre><code> public function mergeObjectVectors(v1:Vector.&lt;Object&gt;, v2:Vector.&lt;Object&gt;):Vector.&lt;Object&gt; { var dictionary:Dictionary = new Dictionary(); var concat:Vector.&lt;Object&gt; = v1.concat(v2); var result:Vector.&lt;Object&gt; = new Vector.&lt;Object&gt;(); for each(var i:Object in concat) { if (!dictionary[i]) { dictionary[i] = true; result.push(i); } } return result; } </code></pre> <p>However if you plan on accepting vectors of any type, it's different:</p> <pre><code> public function testing():void { var v1:Vector.&lt;Object&gt; = new Vector.&lt;Object&gt;(); v1.push({name:"Object 1"}); v1.push({name:"Object 2"}); // Vector w duplicates var v2:Vector.&lt;Object&gt; = new Vector.&lt;Object&gt;(); var o:Object = {name:"Object 3"}; v2.push(o); v2.push(o); v2.push(o); var resultVector:Vector.&lt;Object&gt; = mergeAnything(v1, v2, Class(Vector.&lt;Object&gt;)); var resultArray:Array = mergeAnything(v1, v2, Array); var resultObject:Object = mergeAnything(v1, v2, Object); } public function mergeAnything(o1:Object, o2:Object, resultClass:Class):* { var dictionary:Dictionary = new Dictionary(); var result:Object = new resultClass(); var i:int; for each(var o:Object in o1) { if (!dictionary[o]) { dictionary[o] = true; result[i++] = o; } } for each(o in o2) { if (!dictionary[o]) { dictionary[o] = true; result[i++] = o; } } return result; } </code></pre> <p>The first example will be more resource-efficient.</p> <hr> <p>EDIT: This should do it, try it with your example:</p> <pre><code> public function mergeObjectVectors(v1:Vector.&lt;Object&gt;, v2:Vector.&lt;Object&gt;):Vector.&lt;Object&gt; { var concat:Vector.&lt;Object&gt; = v1.concat(v2); var result:Vector.&lt;Object&gt; = new Vector.&lt;Object&gt;(); var n:int = concat.length; loop:for (var i:int = 0; i &lt; n; i++) { var objectToAdd:Object = concat[i]; var m:int = result.length; for (var j:int = 0; j &lt; m; j++) { var addedObject:Object = result[j]; if (this.areObjectsIdentical(objectToAdd, addedObject)) { continue loop; } } result.push(objectToAdd); } return result; } private function areObjectsIdentical(o1:Object, o2:Object):Boolean { var numComparisons:int = 0; for (var s:String in o1) { numComparisons++; if (o1[s] != o2[s]) { return false; } } for (s in o2) { numComparisons--; } return !numComparisons; } </code></pre>
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    1. COWell it seems that you're allowed to cast an Array as a Vector, so all you have to do is return an Array and cast it as a vector.
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    2. COmuch like my previous attempts, neither can i seem to get your first example to work. i'm passing the function 2 vectors, both of which contain this object with identical key/value pairs: `{city:"Montreal", age:369}`, but both are still being added to the resulting vector.
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    3. COEven if they contain identical information they would be different objects (instanced twice) so the resulting vector would include both objects, but that should also happen with the arrays.
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