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plurals

POGet form popup upon successful submission
primarykey
Id
7115196
data
AcceptedAnswerId
0
AnswerCount
3
ClosedDate
CommentCount
1
CommunityOwnedDate
CreationDate
2011-08-18T23:04:47.993
FavoriteCount
0
LastActivityDate
2011-08-19T01:45:38.443
LastEditDate
LastEditorUserId
0
OwnerUserId
886187
ParentId
0
PostTypeId
1
Score
0
ViewCount
3743
LastEditorDisplayName
text
Body
<p>How do I go about getting this form to display "Submitted" using basic javascript popup window upon successful submission?</p> <pre><code><!DOCTYPE html> <html> <head> <title>Site :: </title> <link rel="stylesheet" media="screen" href="css/wicahost.css" /> <link rel="stylesheet" media="screen" href="css/global.css" /> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.js"></script> <?php require_once('inc/php/clearfieldJs.php'); ?> <script type="text/javascript"> $(document).ready(function() { $("#splashtease").RSV({ rules: [ "required,emAdd,Please enter your email address.", "valid_email,emAdd,Please enter a valid email address.", ] }); }); </script> </head> <body> <script src="http://www.benjaminkeen.com/software/rsv/jquery/jquery.rsv.js"></script> <div id="splashTeaserBox"> <h1 class="wicasplashcenter">Signup!</h1> <div class="wicasplashcenter">Captivating interests and inspiring collaboration.</div> <form id="splashtease" action="inc/subscribe.php" method="post"> <?php $usrBrowser = $_SERVER['HTTP_USER_AGENT']; $todayDt = date('Y-m-d'); ?> <input type="text" name="emAdd" class="splashtease" value="Your Email Address ..." onFocus="clearText(this)" /> <input type="hidden" name="brwsr" value="<?php echo $usrBrowser; ?>" style="margin:0; padding:0;" /> <input type="hidden" name="dt" value="<?php echo $todayDt; ?>" style="margin:0; padding:0;" /> <input type="submit" name="submit" value="" class="splashteasesub" /> </form> </div></body> </html> </code></pre> <p><strong>PHP</strong></p> <pre><code> <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="dnbame"; // Database name $tbl_name="subscriber"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); /* Obliterate bad input */ $goodEmail = mysql_real_escape_string($_POST['emAdd']); $goodBrowser = mysql_real_escape_string($_POST['brwsr']); $goodDate = mysql_real_escape_string($_POST['dt']); $sql= "INSERT INTO subscriber (Email, Browser, DateSubscribed) VALUES('$goodEmail','$goodBrowser','$goodDate')"; $result = mysql_query($sql); if (!$result) { die('Invalid Email, please retry.'); } else{ echo var success; } ?> </code></pre>
Tags
<javascript><html>
Title
Get form popup upon successful submission
singulars
PostAcceptedAnswerId
1. This table or related slice is empty.
PostParentId
1. This table or related slice is empty.
PostTypePostTypeId
1. PTQuestion
UserLastEditorUserId
1. This table or related slice is empty.
UserOwnerUserId
1. USuser886187
plurals
PostLinksPostIdRelatedPostId
1. This table or related slice is empty.
PostLinksRelatedPostIdPostId
1. This table or related slice is empty.
PostsAcceptedAnswerId
1. This table or related slice is empty.
PostsParentIdCreationDate
1. PO
  singulars
  PostTypePostTypeId
  PTAnswer
2. PO
  singulars
  PostTypePostTypeId
  PTAnswer
3. PO
  singulars
  PostTypePostTypeId
  PTAnswer
VotesPostIdCreationDate
1. This table or related slice is empty.
CommentsPostId
1. COYour php is outputing 'var success' which seems to be in error. So normally the server only responds to requests and the echo output would be its response on successful submit. Normally the response is a new page which in which you may test for whatever you write in 'echo whatever' and rewrite using javascript.
  singulars
  PostPostId
  POGet form popup upon successful submission
  UserUserId
  USmozillanerd

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