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POhow to substract two datetime.time values in django template,and how to format a duration as hour,minutes
 

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  1. POhow to substract two datetime.time values in django template,and how to format a duration as hour,minutes
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    <p>In a django app ,I am sending a list of <code>Entry</code> objects to the template.Each <code>Entry</code> object has a start, end times which are datetime.time values(from <code>TimeFields</code> on the form).While listing the Entry objects,I need to show the duration for each entry.Putting a duration field in model seemed to be reduntant since ,start and end times were already there</p> <p>model</p> <pre><code>class Entry(models.Model): title = models.CharField(unique=True,max_length=50) starttime=models.TimeField(null=True) endtime=models.TimeField(null=True) ... </code></pre> <p>template</p> <pre><code>{% for entry in object_list %} &lt;tr&gt; &lt;td&gt; {{entry.title}} &lt;/td&gt; &lt;td&gt; {{entry.starttime}}&lt;/td&gt; &lt;td&gt; {{entry.endtime}}&lt;/td&gt; &lt;td&gt; want to show duration here &lt;/td&gt; {%endfor %} </code></pre> <p><code>1.</code>Is there any filter which can take two datetime.time values and calculate the duration in seconds. ie,</p> <pre><code>given t1=datetime.time(2,30,50) and t2=datetime.time(3,00,50) should show 30 minutes </code></pre> <p><code>2.</code>Also,is there a filter,that can show a duration in given number of minutes as hour,minutes if the minutes value is greater than 60</p> <p>ie,</p> <pre><code>if duration is 50 minutes ==&gt; 50 minutes if duration is 150 minutes ==&gt; 2 hours,30 minutes </code></pre> <p><strong>update</strong></p> <pre><code>def diff_in_time(start,end): startdelta=datetime.timedelta(hours=start.hour,minutes=start.minute,seconds=start.second) enddelta=datetime.timedelta(hours=end.hour,minutes=end.minute,seconds=end.second) return (enddelta-startdelta).seconds/60 </code></pre> <p>when i tried with some sample time values ,it gave me the expected result</p> <pre><code>#start 11:35:00 pm #end 00:05:00 am start= datetime.time(23,35,00) end = datetime.time(00,05,00) print diff_in_time(start,end) ==&gt; 30 minutes #start 00:35:00 am #end 01:35:00 am start= datetime.time(00,35,00) end = datetime.time(01,35,00) print diff_in_time(start,end) ==&gt;60 minutes </code></pre>
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    1. COSuch a shrewd and fine trick !!! Did you find that yourself ? or did you see it in a recipe from Alex Martelli ? or did you come to this trick by chance ? There's nothing to add. If the two times are within less than 24 hours one from the other , this solution is perfect. I see no possible particular case, it will always work. I hope you understand the reason of such a behavior : the internal representation of a timedelta instance is based on 3 attributes **days** , **seconds** and **microseconds**, among them only **days** may have a negative value. Then for a negative timedelta,
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    2. COthe values are adapted so that **seconds** and **microseconds** be positive , representing a lapse of time from an anterior day registered as negative. In a way, 24 hours are sustracted from the number of days, and 24 hours are added to the number of seconds: one compensates the other, but the number of seconds has its value augmented with 24, as is needed. Clever !
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    3. COthanks for the great comment..
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