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  1. PO
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    <p>Just calculate <code>Top</code> and <code>Bottom</code> values for each <code>MyClass</code>.</p> <p>Use a <code>Boundary</code> variable, initializing it to <code>0</code>.</p> <ol> <li><p>Pick an element with biggest height (<code>Bottom</code> - <code>Top</code>), whose <code>Top</code> = <code>Boundary</code>. If some elements are ax equo (same <code>Top</code>, same height), pick the one on the left.</p></li> <li><p>Shift (set) <code>Boundary</code> to <code>Bottom</code> of this element (this ensures that the next element you pick will not overlap with this one).</p></li> <li><p>Go to <code>1</code>.</p></li> </ol> <p>When going horizontally, just use <code>Left</code> instead of <code>Top</code> etc.</p> <p>Given your requirements (<em>"Will they always fit nicely together like a puzzle as you have it?"</em> - you reply <em>"yes it will always fit together"</em>) it would work as you described: 1, 4, 8.</p> <p><strong>Edit:</strong> okay. Then we just pick an element whose Top is GREATER or equal than the previous element's Bottom.</p> <p>Something along the lines of:</p> <pre><code>public List&lt;MyClass&gt; GetBiggestNotOverlappingVertically(ICollection&lt;MyClass&gt; elements) { var result = new List&lt;MyClass&gt;(); var boundary = 0; var stop = false; Func&lt;MyClass, MyClass, bool&gt; inTheSameLane = (first, second) =&gt; ((first.Left &gt;= second.Left &amp;&amp; first.Left &lt;= second.Right) || (first.Right &lt;= second.Right &amp;&amp; first.Right &gt;= second.Left)); while (!stop) { var nextElement = (from element in elements where element.Top &gt;= boundary &amp;&amp; // and where we are NOT "jumping over" any element in the same lane: // there's no element between the two (in the same lane, that is) !(from otherElement in elements where otherElement != element &amp;&amp; inTheSameLane(element, otherElement) &amp;&amp; otherElement.Top &gt;= boundary &amp;&amp; otherElement.Bottom &lt;= element.Top select otherElement).Any() orderby element.Height descending, element.Left ascending select element).FirstOrDefault(); stop = nextElement == null; if (!stop) { result.Add(nextElement); boundary = nextElement.Bottom; } } return result; } </code></pre>
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    1. POget the biggest not overlapping objects algorithm (x, y, width, height)
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    1. USKonrad Morawski
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    1. COsorry ! I've made a mistake its don't always fit together. There can be space between elements.
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    2. COOkay... I adjusted my suggestion accordingly and I put together some sample code for a try.
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    3. CO@Vibo, how does that help if you have a stack of small items that is bigger than a single item, all starting from the top?
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