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    <p><strong>ORIGINAL ANSWER (Scratch it)</strong></p> <p><code>Uri.toString</code> writes out a description of the URI object from the class Uri.</p> <p>Documentation is here: <a href="http://developer.android.com/reference/android/net/Uri.html" rel="nofollow">http://developer.android.com/reference/android/net/Uri.html</a></p> <p>To get the human readable version, invoke the getter methods defined for the class.</p> <p><strong>THE REAL ANSWER</strong></p> <p>The OP has clarified and provided the actual code. Here is the actual context:</p> <pre><code>@Override protected Document doInBackground(Uri... arg0) { Document ret = null; Log.v("HTTPGet", "Uri.toString == " + arg0.toString()); try { ret = Jsoup.connect(arg0.toString()).get(); } catch (IOException e) { e.printStackTrace(); } return ret; } </code></pre> <p>What is happening here is that the parameter <code>arg0</code> has type <code>Uri[]</code>, namely an <strong>array of Uri</strong>. The dot-dot-dot syntax is Java's "varargs". It means the parameter is actually an array, but rather than passing an array in the call, you can pass any number of arguments that Java will bundle up into an array.</p> <p>Because you are using a third party library, you have to override this method which takes in one <strong>or more</strong> Uris. You are assuming that only one will be used. If this is the case, you should instead write</p> <pre><code>Log.v("HTTPGet", "Uri.toString == " + arg0[0].toString()); </code></pre> <p>If you really will be processing multiple uris, use a for-loop to go through and log all of them.</p> <p>Make sure to fix your <code>Jsoup.connect</code> line too. It doesn't want a messy array string. :)</p>
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    1. COActually, the documentation says that `toString` "returns the encoded string representation of this URI. Example: "http://google.com/". The behaviour OP is experiencing is therefore unexpected, to say the least.
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    2. COIn that case convert the android Uri to a Java URI and call `toString` on that: information at http://stackoverflow.com/questions/559902/android-how-can-i-convert-android-net-uri-object-to-java-net-uri-object
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    3. CO@Xion Agreed that this is odd, `[L` indicates an array.
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