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POPython: Getting files into an archive without the directory?
 

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  1. POPython: Getting files into an archive without the directory?
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    <p>I've been learning python for about 3 weeks now, and I'm currently trying to write a little script for sorting files (about 10.000) by keywords and date appearing in the filename. Files before a given date should be added to an archive. The sorting works fine, but not the archiving</p> <p>It creates an archive - the name is fine - but in the archive is the complete path to the files. If i open it, it looks like: <code>folder1 -&gt; folder2 -&gt; folder3 -&gt; files</code>.</p> <p>How can I change it such that the archive only contains the files and not the whole structure?</p> <p>Below is a snippet with my zip function, <code>node</code> is the path where the files were before sorting, <code>folder</code> is a subfolder with the files sorted by a keyword in the name, <code>items</code> are the folders with files sorted by date.</p> <p>I am using Python 2.6</p> <pre><code>def ZipFolder(node, zipdate): xynode = node + '/xy' yznode = node + '/yz' for folder in [xynode,yznode]: items = os.listdir(folder) for item in items: itemdate = re.findall('(?&lt;=_)\d\d\d\d-\d\d', item) print item if itemdate[0] &lt;= zipdate: arcname = str(item) + '.zip' x = zipfile.ZipFile(folder + '/' + arcname, mode='w', compression = zipfile.ZIP_DEFLATED) files = os.listdir(folder + '/' + item) for f in files: x.write(folder + '/' + item + '/' + f) print 'writing ' + str(folder + '/' + item + '/' + f) + ' in ' + str(item) x.close() shutil.rmtree(folder + '/' + item) return </code></pre> <p>I am also open to any suggestions and improvements.</p>
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