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POConverting a data frame to a matrix with plyr daply
 

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  1. POConverting a data frame to a matrix with plyr daply
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    <p>I'm trying to use the <code>daply</code> function in the <code>plyr</code> package but I cannot get it to output properly. Even though the variable that makes up the matrix is numeric, the elements of the matrix are lists, not the variable itself. Here is a small subset of the data for example sake:</p> <pre><code> Month Vehicle Samples 1 Oct-10 31057 256 2 Oct-10 31059 316 3 Oct-10 31060 348 4 Nov-10 31057 267 5 Nov-10 31059 293 6 Nov-10 31060 250 7 Dec-10 31057 159 8 Dec-10 31059 268 9 Dec-10 31060 206 </code></pre> <p>And I would like to be able to visualize the data in a matrix format, which would look something like this:</p> <pre><code> Month Vehicle Oct-10 Nov-10 Dec-10 31057 256 267 159 31059 316 293 268 31060 348 250 206 </code></pre> <p>Here are a couple of alternative syntax that I use (the latter because my original dataframe has more columns than I show here):</p> <pre><code>daply(DF, .(Vehicle, Month), identity) daply(DF,.(Vehicle,Month), colwise(identity,.(Samples))) </code></pre> <p>However what I get instead is rather abstruse:</p> <pre><code> Month Vehicle Oct-10 Nov-10 Dec-10 31057 List,3 List,3 List,3 31059 List,3 List,3 List,3 31060 List,3 List,3 List,3 </code></pre> <p>I used the <code>str</code> function on the output as some commenters have suggested, and here is an excerpt:</p> <pre><code>List of 9 $ :'data.frame': 1 obs. of 3 variables: ..$ Month : Ord.factor w/ 3 levels "Oct-10"&lt;"Nov-10"&lt;..: 1 ..$ Vehicle: Factor w/ 3 levels "31057","31059",..: 1 ..$ Samples: int 256 $ :'data.frame': 1 obs. of 3 variables: ..$ Month : Ord.factor w/ 3 levels "Oct-10"&lt;"Nov-10"&lt;..: 1 ..$ Vehicle: Factor w/ 3 levels "31057","31059",..: 2 ..$ Samples: int 316 </code></pre> <p>What am I missing? Also, is there a way to do this simply with the base packages? Thanks!</p> <p>Below is the <code>Dput</code> of the data frame if you'd like to reproduce this:</p> <pre><code>structure(list(Month = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L), .Label = c("Oct-10", "Nov-10", "Dec-10"), class = c("ordered", "factor")), Vehicle = structure(c(1L, 2L, 3L, 1L, 2L, 3L, 1L, 2L, 3L), .Label = c("31057", "31059", "31060"), class = "factor"), Samples = c(256L, 316L, 348L, 267L, 293L, 250L, 159L, 268L, 206L)), .Names = c("Month", "Vehicle", "Samples"), class = "data.frame", row.names = c(NA, 9L)) </code></pre>
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    1. USJD Margulici
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    1. COA bit more information would be useful. Try str(DF) and paste the output in the question. Or use dput(DF) to provide people with your data to work with if it's not to big (subset it down if it is).
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    2. COIt's not obvious what you are trying to do here. It seems that you are attempting some kind of reshape of the data, since `identity` doesn't perform any operations on its arguments. Please tell us what your expected results are.
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      1. USAndrie
    3. COSee http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example on how to make your code in your question reproducible.
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      1. USRoman Luštrik
 

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