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POHow to convert xml layer-list to layerdrawable by code
 

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  1. POHow to convert xml layer-list to layerdrawable by code
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    <p>I am trying to code the following xml by code.</p> <p>----drawable\my_layerdrawable.xml</p> <pre><code>&lt;?xml version="1.0" encoding="utf-8"?&gt; &lt;layer-list xmlns:android="http://schemas.android.com/apk/res/android"&gt; &lt;item&gt; &lt;bitmap android:src="@drawable/my_image" android:gravity="left"/&gt; &lt;/item&gt; &lt;item android:left="10dp"&gt; &lt;bitmap android:src="@drawable/my_image" android:gravity="left" /&gt; &lt;/item&gt; &lt;item android:top="10dp"&gt; &lt;bitmap android:src="@drawable/my_image" android:gravity="left"/&gt; &lt;/item&gt; &lt;item android:top="10dp" android:left="10dp"&gt; &lt;bitmap android:src="@drawable/my_image" android:gravity="left" /&gt; &lt;/item&gt; &lt;item android:top="20dp"&gt; &lt;bitmap android:src="@drawable/my_image" android:gravity="left"/&gt; &lt;/item&gt; &lt;item android:top="20dp" android:left="10dp"&gt; &lt;bitmap android:src="@drawable/my_image" android:gravity="left" /&gt; &lt;/item&gt; &lt;/layer-list&gt; </code></pre> <p>I coded the following block but it is stretching the images.</p> <pre><code> InsetDrawable[] layers = new InsetDrawable[this.itemCount]; Resources resources = getResources(); ImageButton imgButton = (ImageButton) findViewById(R.id.btnItems); int layerTop = 0; for (int i = 0; i &lt; this.itemCount; i++) { int layerLeft = i % 2 == 1 ? 5 : 0; Drawable dr = resources.getDrawable(R.drawable.my_image); layers[i] = new InsetDrawable(dr, layerLeft, layerTop, -layerLeft, -layerTop); layerTop += i % 2 == 1 ? 10 : 0; } LayerDrawable layerDrawable = new LayerDrawable(layers); imgButton.setImageDrawable(layerDrawable); </code></pre> <p>When I assign the drawable xml to the <code>imgButton</code> It is working correctly no stretch or any change.</p> <pre><code>ImageButton imgButton = (ImageButton) findViewById(R.id.btnItems); imgButton.setImageResource(R.drawable.my_layerdrawable); </code></pre> <p>Do you have any idea to make the layer drawable by code?</p> <p>Thanks.</p>
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