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    <p>I haven't heard of any such app… But I don't expect it would be too hard to build.</p> <p>If I were doing it, I would put a permissions check in the entry points to each app. For example:</p> <pre><code>check_app_permission = lambda request: permissions.check_app_permission("blog", request) def view_blog(request, …): check_app_permission(request) … </code></pre> <p>(it might even be possible to do some magic and inject this check at the <code>urls.py</code> level…)</p> <p>Additionally, I would create a <code>has_app_permission</code> template tag:</p> <pre><code>&lt;div id="sidebar"&gt; {% if has_app_permission "blog" %} {% include "blog/sidebar_recent_posts.html" %} {% endif %} &lt;/div&gt; </code></pre> <p>Or similar.</p> <p>Finally, there are approximately a million ways you <em>could</em> implement the permission system… And without more information I wouldn't be able to comment. The simplest, though, would be something like this:</p> <pre><code>class App(Model): name = CharField(…) class AppPermission(object): app = ForeignKey(App) user = ForiegnKey(User) def user_has_permission(user, app_name): return AppPermission.objects.filter(app__name=app_name, user=user).exists() </code></pre> <p>I would avoid trying to do this with middleware, because if I understand the problem correctly, I expect you will (or, at least, I expect I would) end up spending a bunch of time building a generic framework which, in the end, would just have checks similar to those above.</p> <p>Does that help? Is there something I can clarify?</p>
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    1. USDavid Wolever
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    1. COOk, so instead of writing generic app with miidleware You suggest just paste permission check at every app? Surly looks easier for me. Probably do as You suggest. thanks.
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    2. COYup, that's what I'd do. That way the apps have the opportunity to decide exactly what they allow… For example, you might want the “tagging” app to allow limited access (maybe you can pick from a predefined set of tags)… That would be tricky with middleware, but easy this way.
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