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    <p>You can clone an array by calling <code>slice</code> directly:</p> <pre><code>var arr2 = arr1.slice(); </code></pre> <p>If you want a <code>clone</code> function, you can do:</p> <pre><code>var clone = function(arr) { return arr.slice(); }; </code></pre> <p>If you really want to prototype function (which is not necessary as long as the function is not overwritten):</p> <pre><code>var clone = function(arr) { return [].slice.call(arr); }; </code></pre> <hr> <p><strong>Why can't you reference <code>call</code> or <code>apply</code> directly?</strong></p> <p>It does not work for the same reason assigning a method of an object to a variable does not "work". </p> <p>If you call <code>func.call()</code> then <code>this</code> inside <code>call</code> will be a reference to <code>func</code>, a function object.</p> <p>If you assign <code>call</code> to a variable then the context is lost. You have a reference to the generic <code>call</code> function. Thus you'd have to pass the correct context (the method you want to apply <code>call</code> to) as first parameter to <code>call</code> again:</p> <pre><code>var clone = [].slice.call; var arr2 = clone.call([].slice, arr1); </code></pre> <p>This is not really an improvement and quite confusing.</p> <p><code>call</code> and <code>apply</code> are methods that every functions inherits from <code>Function.prototype</code>. Functions don't have their own version of them. <code>[].slice.call === [].splice.call</code> yields <code>true</code>.</p>
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    1. POHow do you reference Array.prototype.slice.call()?
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    1. USFelix Kling
    1. USFelix Kling
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    1. COThanks for the effort, but I am not asking for a cloning function so much as I am asking why I can't seem to use a reference to the call function or apply function of another function.
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      1. USClarence Fredericks
    2. CO@Clarence: See my latest update.
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      1. USFelix Kling
    3. COThanks for the update. This is just what I was missing.
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