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    <p>This is a bit tricky. For instance, the following code:</p> <pre><code>import sys import os z = sys.argv[0] p = os.path.dirname(z) f = os.path.abspath(p) print "argv[0]={0} , dirname={1} , abspath={2}\n".format(z,p,f) </code></pre> <p>gives this output on Windows</p> <p><code>argv[0]=../zzz.py , dirname=.. , abspath=C:\Users\michael\Downloads</code> First of all, notice that argv has the slash which I typed in the command <code>python ../zzz.py</code> and the absolute path has the normal Windows backslashes. If you need to be cross platform you should probably refrain from putting regular slashes on Python command lines, and use <code>os.sep</code> to refer to the character that separated pathname components.</p> <p>So far I have only partly answered your question. There are a couple of ways to use the value of <code>f</code> to get what you want. Brute force is to use something like:</p> <pre><code>targetpath = f + os.sep + ".." + os.sep + ".." </code></pre> <p>which would result in something like <code>C:\Users\michael\Downloads\..\..</code> on Windows and <code>/home/michael/../..</code> on Unix. Each .. goes back one step and is the equivalent of removing the pathname component.</p> <p>But you could do better by breaking up the path:</p> <pre><code>target = f.split(os.sep) targetpath = os.sep.join(target[:-2] </code></pre> <p>and rejoining all but the last two bits to get <code>C:\Users</code> on Windows and <code>/</code> on Unix. If you do that it might be a good idea to check that there are enough pathname components to remove.</p> <p>Note that I ran the program above by typing <code>python ../xxx.py</code>. In other words I was not in the same working directory as the script, therefore getcwd() would not be useful.</p>
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