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    <p>The code in <code>Assembly1.ClassA</code> doesn't know that it's called in a separate thread from <code>Assembly2.ClassB</code>, so I'd consider it bad style to introduce a mechanism where <code>Assembly1.ClassA.task1</code> signals that it's done.</p> <p>For your scenario, it looks like you just need to call <a href="http://msdn.microsoft.com/en-us/library/95hbf2ta.aspx" rel="nofollow">Thread.Join</a>:</p> <blockquote> <p><strong>Thread.Join Method</strong></p> <p>Blocks the calling thread until a thread terminates</p> </blockquote> <p><em>Example:</em></p> <pre><code>private void Main() { Thread newThread = new Thread(new ThreadStart(Assembly1.ClassA.Task1)); // Start thread newThread.Start(); // Wait until the invoked method returns newThread.Join(); // Do the rest ... } </code></pre> <p>Note that this is just the same as</p> <pre><code>private void Main() { // Invoke method and wait until invoked method returns Assembly1.ClassA.Task1(); // Do the rest ... } </code></pre> <p>So I guess I don't understand your question.</p> <hr> <p>Based on your updated question, I'd say that <code>Assembly1.ClassA</code> should be the one resposible for spinning up the thread:</p> <pre><code>public class ClassA { private Socket socket; private Thread thread; public void Connect() { socket = new Socket(...); socket.Connect(...); thread = new Thread(DoWork); thread.Start(); } public void Disconnect() { socket.Shutdown(SocketShutdown.Both); socket.Close(); thread.Join(); } private void DoWork() { try { while (true) { int received = socket.Receive(buffer, ...); if (received == 0) { break; } // process buffer ... } } catch (SocketException) { ... } } } </code></pre>
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    1. POCan I use ManualResetEvent across assemblies?
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    1. COWhat if I need to keep the thread alive? In other words, in the code snippet, only a few lines are required that all threads are to stop. After that, the new thread could last a while, that would certainly block the calling thread, right?
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    2. CO@Ed Gl: Can you expand on what these few special lines do? Could a `lock` be more appropriate than a signal?
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    3. COI will post an edit to clarify...
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