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    <p>Here is an updated answer</p> <pre><code>var newFunc = oldFunc.bind({}); //clones the function with '{}' acting as it's new 'this' parameter </code></pre> <p>However ".bind" is a modern ( >=iE9 ) feature of JavaScript (with a compatibility workaround from MDN)</p> <p><a href="https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Function/bind" rel="noreferrer">https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Function/bind</a></p> <p><strong>Note:</strong> that it <strong>does not clone</strong> the function object additional attached <strong>properties</strong>, <strong>including</strong> the <strong>prototype</strong> property. Credit to <a href="https://stackoverflow.com/users/554406/">@jchook</a></p> <p><strong>Note:</strong> that the new function <strong>this</strong> variable is stuck with the argument given on bind(), even on new function apply() calls. Credit to <a href="https://stackoverflow.com/users/700980/">@Kevin</a></p> <pre><code>function oldFunc() { console.log(this.msg); } var newFunc = oldFunc.bind( { msg:"You shall not pass!" } ); // this object is binded newFunc.apply( { msg:"hello world" } ); //logs "You shall not pass!" instead </code></pre> <p><strong>Note:</strong> binded function object, instanceof treats newFunc/oldFunc as the same. Credit to <a href="https://stackoverflow.com/users/59272">@Christopher</a></p> <pre><code>(new newFunc()) instanceof oldFunc; //gives true (new oldFunc()) instanceof newFunc; //gives true as well newFunc == oldFunc; //gives false however </code></pre>
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    1. CONote that `newFunc` will NOT have its own prototype for `new newFunc` instances, while `oldFunc` will.
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