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    <p>According to <a href="http://code.activestate.com/recipes/534137/" rel="nofollow noreferrer">Generate a Regular Expression to Match an Arbitrary Numeric Range</a>, and after generating such a regex for your example at <a href="https://web.archive.org/web/20151029043426/http://utilitymill.com/utility/Regex_For_Range" rel="nofollow noreferrer">Regex_For_Range</a>:</p> <pre><code>\b0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4])\b </code></pre> <p>would do the trick.</p> <p>The process would be (still following that Regex generator):</p> <blockquote> <p>First, break into equal length ranges:</p> </blockquote> <pre><code>110 - 999 1000 - 2234 </code></pre> <blockquote> <p>Second, break into ranges that yield simple regexes:</p> </blockquote> <pre><code>110 - 199 200 - 999 1000 - 1999 2000 - 2199 2200 - 2229 2230 - 2234 </code></pre> <blockquote> <p>Turn each range into a regex:</p> </blockquote> <pre><code>1[1-9][0-9] [2-9][0-9]{2} 1[0-9]{3} 2[01][0-9]{2} 22[0-2][0-9] 223[0-4] </code></pre> <blockquote> <p>Collapse adjacent powers of 10: 1[1-9][0-9] [2-9][0-9]{2} 1[0-9]{3} 2[01][0-9]{2} 22[0-2][0-9] 223[0-4]</p> <p>Combining the regexes above yields:</p> </blockquote> <pre><code>0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4]) </code></pre> <blockquote> <p>Next we'll try factoring out common prefixes using a tree:<br> Parse into tree based on regex prefixes:</p> </blockquote> <pre><code>. 1 [1-9] [0-9] + [0-9]{3} + [2-9] [0-9]{2} + 2 [01] [0-9]{2} + 2 [0-2] [0-9] + 3 [0-4] </code></pre> <blockquote> <p>Turning the parse tree into a regex yields:</p> </blockquote> <pre><code>0*(1([1-9][0-9]|[0-9]{3})|[2-9][0-9]{2}|2([01][0-9]{2}|2([0-2][0-9]|3[0-4]))) </code></pre> <blockquote> <p>We choose the shorter one as our result.</p> </blockquote> <pre><code>\b0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4])\b </code></pre>
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