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    <p>You can use what's called a numbers table. Just create a table with as many rows as there are days between your dates, number them sequentially.</p> <p>Here's a pretty slick way to create a numbers table in SQL 2008, may also work in 2005: <a href="http://archive.msdn.microsoft.com/SQLExamples/Wiki/View.aspx?title=NumbersTable" rel="nofollow">http://archive.msdn.microsoft.com/SQLExamples/Wiki/View.aspx?title=NumbersTable</a></p> <p>Alternatively, you just create a table with an identity and then insert TOP x rows into it.</p> <p>From there you can compute the rest</p> <pre><code>number 1 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) 2 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) 3 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) 4 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) 5 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) 6 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) 7 DateAdd(dd, '2011/07/20', number) DatePart(dw, DateAdd(dd, '2011/07/20', number)) </code></pre> <p>Join that table to your original results, and then insert the product into your final table.</p> <p>Query:</p> <pre><code>SELECT TOP 5000 IDENTITY( INT, 0, 1 ) AS N INTO Number FROM sys.objects a, sys.objects b, sys.objects c SELECT N, DATEADD(dd, N, '7/20/2011') AS Date, DATEPART(dw, DATEADD(dd, N, '7/20/2011')) AS DayofWeek FROM Number WHERE DATEADD(dd, N, '7/20/2011') BETWEEN '7/20/2011' AND '8/17/2011' </code></pre> <p>Result:</p> <pre><code>N Date DayofWeek ----------- ----------------------- ----------- 0 2011-07-20 00:00:00.000 4 1 2011-07-21 00:00:00.000 5 2 2011-07-22 00:00:00.000 6 3 2011-07-23 00:00:00.000 7 4 2011-07-24 00:00:00.000 1 5 2011-07-25 00:00:00.000 2 6 2011-07-26 00:00:00.000 3 7 2011-07-27 00:00:00.000 4 8 2011-07-28 00:00:00.000 5 9 2011-07-29 00:00:00.000 6 10 2011-07-30 00:00:00.000 7 11 2011-07-31 00:00:00.000 1 12 2011-08-01 00:00:00.000 2 13 2011-08-02 00:00:00.000 3 14 2011-08-03 00:00:00.000 4 15 2011-08-04 00:00:00.000 5 16 2011-08-05 00:00:00.000 6 17 2011-08-06 00:00:00.000 7 18 2011-08-07 00:00:00.000 1 19 2011-08-08 00:00:00.000 2 20 2011-08-09 00:00:00.000 3 21 2011-08-10 00:00:00.000 4 22 2011-08-11 00:00:00.000 5 23 2011-08-12 00:00:00.000 6 24 2011-08-13 00:00:00.000 7 25 2011-08-14 00:00:00.000 1 26 2011-08-15 00:00:00.000 2 27 2011-08-16 00:00:00.000 3 28 2011-08-17 00:00:00.000 4 </code></pre>
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    1. POT-SQL task - find all dates with specified WeekDays in two dates range
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    1. USLucent Fox
    1. USLucent Fox
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    1. COHi Lucent, thx for the query, it explains me a lot! Looks very promising (like a solution indeed ;)) I will test it and let you know, THX a lot!!
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      1. USbinball
    2. COMark it as the answer if it works out for ya ^_^
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    3. COI surgest not choosing an answer right away. 30 minutes is not really fair to decide the best sql. Let it sip for half a day. Then come back and choose the best solution.
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      1. USt-clausen.dk
 

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