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POHow can I arrange an arbitrary number of ggplots using grid.arrange?
 

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  1. POHow can I arrange an arbitrary number of ggplots using grid.arrange?
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    <p><strong><em>This is cross-posted on the ggplot2 google group</em></strong></p> <p>My situation is that I'm <a href="https://github.com/briandk/granova/blob/dev/R/granova.contr.ggplot.R" rel="noreferrer" title="Click here to see the development repository for our graphical analysis of variance package in R">working on a function</a> that outputs an arbitrary number of plots (depending upon the input data supplied by the user). The function returns a list of n plots, and I'd like to lay those plots out in 2 x 2 formation. I'm struggling with the simultaneous problems of:</p> <ol> <li>How can I allow the flexibility to be handed an arbitrary (n) number of plots?</li> <li>How can I also specify I want them laid out 2 x 2</li> </ol> <p>My current strategy uses <code>grid.arrange</code> from the <code>gridExtra</code> package. It's probably not optimal, especially since, and this is key, <em>it totally doesn't work</em>. Here's my commented sample code, experimenting with three plots:</p> <pre><code>library(ggplot2) library(gridExtra) x &lt;- qplot(mpg, disp, data = mtcars) y &lt;- qplot(hp, wt, data = mtcars) z &lt;- qplot(qsec, wt, data = mtcars) # A normal, plain-jane call to grid.arrange is fine for displaying all my plots grid.arrange(x, y, z) # But, for my purposes, I need a 2 x 2 layout. So the command below works acceptably. grid.arrange(x, y, z, nrow = 2, ncol = 2) # The problem is that the function I'm developing outputs a LIST of an arbitrary # number plots, and I'd like to be able to plot every plot in the list on a 2 x 2 # laid-out page. I can at least plot a list of plots by constructing a do.call() # expression, below. (Note: it totally even surprises me that this do.call expression # DOES work. I'm astounded.) plot.list &lt;- list(x, y, z) do.call(grid.arrange, plot.list) # But now I need 2 x 2 pages. No problem, right? Since do.call() is taking a list of # arguments, I'll just add my grid.layout arguments to the list. Since grid.arrange is # supposed to pass layout arguments along to grid.layout anyway, this should work. args.list &lt;- c(plot.list, "nrow = 2", "ncol = 2") # Except that the line below is going to fail, producing an "input must be grobs!" # error do.call(grid.arrange, args.list) </code></pre> <p>As I am wont to do, I humbly huddle in the corner, eagerly awaiting the sagacious feedback of a community far wiser than I. Especially if I'm making this harder than it needs to be.</p>
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    1. COKudos on a VERY well done question. I'm going to use this as an example of how to write a good SO [r] question.
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    2. COespecially the "humbly huddling" part -- nothing like a good grovel :-)
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    3. CO@JD and @Ben - I'm flattered, guys. Sincerely. And I really appreciate the help.
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