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    <p>You should be able to do this with a CTE in SQL 2005. Stealing Lievens data:</p> <pre> DECLARE @Attendance TABLE (EmployeeNumber INTEGER, EntryDate DATETIME, Status VARCHAR(1)) INSERT INTO @Attendance VALUES (200, '03/01/2009', 'P') INSERT INTO @Attendance VALUES (200, '03/02/2009', 'A') INSERT INTO @Attendance VALUES (200, '03/03/2009', 'A') INSERT INTO @Attendance VALUES (200, '03/04/2009', 'A') INSERT INTO @Attendance VALUES (200, '04/04/2009', 'A') INSERT INTO @Attendance VALUES (200, '04/05/2009', 'A') INSERT INTO @Attendance VALUES (201, '03/01/2009', 'A') INSERT INTO @Attendance VALUES (201, '03/02/2009', 'A') INSERT INTO @Attendance VALUES (201, '03/03/2009', 'P'); </pre> <p>Then use this CTE to extract the sequence:</p> <pre> WITH Dates ( EntryDate, EmployeeNumber, Status, Days ) AS ( SELECT a.EntryDate, a.EmployeeNumber, a.Status, 1 FROM @Attendance a WHERE a.EntryDate = (SELECT MIN(EntryDate) FROM @Attendance) -- RECURSIVE UNION ALL SELECT a.EntryDate, a.EmployeeNumber, a.Status, CASE WHEN (a.Status = Parent.Status) THEN Parent.Days + 1 ELSE 1 END FROM @Attendance a INNER JOIN Dates parent ON datediff(day, a.EntryDate, DateAdd(day, 1, parent.EntryDate)) = 0 AND a.EmployeeNumber = parent.EmployeeNumber ) SELECT * FROM Dates order by EmployeeNumber, EntryDate </pre> <p>Although as a final note the sequence does seem strange to me, depending on your requirements there may be a better way of aggregating the data? Never the less, this will produce the sequence you require</p>
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    1. POHow to find persons who are absent continuously for n number of days?
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    1. USChris
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    1. POHow to find persons who are absent continuously for n number of days?
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    1. COThank you very much. This works perfectly as expected. Now, I am trying to insert some holidays (H status) and then check it.
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