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POUsing RegEX to match URL pattern, invalid quantifier?
 

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  1. POUsing RegEX to match URL pattern, invalid quantifier?
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    <p>I am trying to use RegEX to match a URL pattern. I found an answer here: <a href="https://stackoverflow.com/questions/5717093/check-if-a-javascript-string-is-an-url">Check if a Javascript string is a url</a></p> <p>Which pointed me to here: <a href="http://forums.devshed.com/javascript-development-115/regexp-to-match-url-pattern-493764.html" rel="nofollow noreferrer">http://forums.devshed.com/javascript-development-115/regexp-to-match-url-pattern-493764.html</a></p> <p>Which gave me the following code(cut and pasted from devshed to here and to my script):</p> <pre><code>function ValidURL(str) { var pattern = new RegExp('^(https?:\/\/)?'+ // protocol '((([a-z\d]([a-z\d-]*[a-z\d])*)\.)+[a-z]{2,}|'+ // domain name '((\d{1,3}\.){3}\d{1,3}))'+ // OR ip (v4) address '(\:\d+)?(\/[-a-z\d%_.~+]*)*'+ // port and path '(\?[;&amp;a-z\d%_.~+=-]*)?'+ // query string '(\#[-a-z\d_]*)?$','i'); // fragment locater if(!pattern.test(str)) { alert("Please enter a valid URL."); return false; } else { return true; } } </code></pre> <p>When I attempt to use it in Firefox 4.0, Firebug 1.7.3 gives me an invalid quantifier error at:</p> <pre><code> '(\#[-a-z\d_]*)?$','i'); // fragment locater </code></pre> <p>Does anyone have an idea on what the issue might be?</p> <p>From other searches on invalid quantifier, I believe that * is an issue but not sure what it might be. The string in question that I am using the function on when it gives me the error is:</p> <pre><code>htp://localhost:1987/ </code></pre> <p><strong>ADDED COMMENT</strong> The fix suggested by agent-j at least removed the invalid quantifier issue. <em>thumbs up</em></p> <p>However, it doesn't like the sample url above when done correctly:</p> <pre><code> http://localhost:1987/ </code></pre> <p>The issue is with the port. When I remove the port #, it likes localhost.</p>
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    1. COOne of the things you'll need to address is that when you form a regex from strings like that, the things you need to quote are *different* than when you form the regex with regex literal syntax. Specifically, you don't need "\" before your "/" characters, but you *do* need to *double* the "\" characters before things like "d" or "?".
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    2. COAlso the line number of the error is probably not interesting, as the actual error won't be detected until the "RegExp()" function is called and the expression is parsed. The problem is probably not, in fact, with that last part of the regular expression.
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    3. CO@Pointy, very good point about the error location not giving the correct spot.
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