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    <p>The main ideas to change the background color of the row you will find <a href="https://stackoverflow.com/questions/4369899/jqgrid-zebra-alt-rows-background-not-working-due-to-ui-theme-class/4382122#4382122">here</a> and <a href="https://stackoverflow.com/questions/2931732/jqgrid-coloring-an-entire-line-in-grid-based-upon-a-cells-value/2936673#2936673">here</a>. I recommend you to read <a href="https://stackoverflow.com/questions/4942761/how-to-change-the-color-of-jqgrid-cell/4943722#4943722">this answer</a> which discussed different advantages and disadvantages of different approaches.</p> <p>To get column index from the column name you can use following simple function:</p> <pre><code>var getColumnIndexByName = function(grid, columnName) { var cm = grid.jqGrid('getGridParam','colModel'),i=0,l=cm.length; for (; i&lt;l; i++) { if (cm[i].name===columnName) { return i; // return the index } } return -1; }; </code></pre> <p>The function <code>getColumnIndexByName($("#list"), 'MyColumnName')</code> will get you the index in <code>colModel</code> of the 'MyColumnName' column.</p> <p>To change the background color you can follow the example</p> <pre><code>loadComplete: function() { $("tr.jqgrow:odd").addClass('myAltRowClass'); } </code></pre> <p>from <a href="https://stackoverflow.com/questions/4369899/jqgrid-zebra-alt-rows-background-not-working-due-to-ui-theme-class/4382122#4382122">the answer</a>, but instead of <code>':odd'</code> filter you can write the filter yourself using <a href="http://api.jquery.com/filter/" rel="nofollow noreferrer">jQuery.filter</a>. Inside of the filter you can use <a href="http://api.jquery.com/nth-child-selector/" rel="nofollow noreferrer">:nth-child()</a> to access the data from the corresponding <code>&lt;td&gt;</code> element (see <a href="https://stackoverflow.com/questions/5010761/linking-from-a-column-value-in-jqgrid-to-a-new-page-using-get/5017528#5017528">here</a>)</p> <p><strong>UPDATED</strong>: You can do the following (very close to the code from <a href="https://stackoverflow.com/questions/5664587/jqgrid-load-large-data-set-without-pagination/5690583#5690583">the another answer</a>):</p> <pre><code>loadComplete: function() { var iCol = getColumnIndexByName($(this),'closed'), cRows = this.rows.length, iRow, row, className; for (iRow=0; iRow&lt;cRows; iRow++) { row = this.rows[iRow]; className = row.className; if ($.inArray('jqgrow', className.split(' ')) &gt; 0) { var x = $(row.cells[iCol]).children("input:checked"); if (x.length&gt;0) { if ($.inArray('myAltRowClass', className.split(' ')) === -1) { row.className = className + ' myAltRowClass'; } } } } } </code></pre> <p>The corresponding demo is <a href="http://www.ok-soft-gmbh.com/jqGrid/SimpleLocalGridChangeRowBackgroundBasedOnCheckboxes.htm" rel="nofollow noreferrer">here</a>. You will see the following:</p> <p><img src="https://i.stack.imgur.com/cg6RJ.png" alt="enter image description here"></p> <p>By the way if the 'Closed' column will be hidden everything will continue to work as before.</p> <p><strong>UPDATED 2</strong>: <a href="https://stackoverflow.com/a/10531680/315935">The answer</a> describe how to use <code>rowattr</code> callback to simplify the solution and to have the best performance (in case of <code>gridview: true</code>).</p>
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    1. COthank you. Colmodel is defined as `{formatter:"checkbox",label:null,name:"Posted",editable:true,classes:null,hidden:true}`. I tried to get value using `$("tbody > tr.jqgrow > td:nth-child("+(i+1)+")", grid[0])` but this returns strange array. How to get posted column value ?
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    2. CO@Andrus: Do you want to find all rows where in the "Posted" column the checkbox is checked and mark the rows with background color (add the "jqgrid-readonlycolumn" class)?
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    3. COYes. Posted column is usually hidden (can switched on by user) so maybe checkbox is not rendered in this case. True / False values are passed from server as json to this column. I want to change background color for rows where Posted column value is True
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