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POPython, redirecting the stream of Popen to a python function
 

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    <p>I'm new to python programming. I have this problem: I have a list of text files (both compressed and not) and I need to : - connect to the server and open them - after the opening of the file, I need to take his content and pass it to another python function that I wrote</p> <pre><code>def readLogs (fileName): f = open (fileName, 'r') inStream = f.read() counter = 0 inStream = re.split('\n', inStream) # Create a 'list of lines' out = "" # Will contain the output logInConst = "" # log In Construction curLine = "" # Line that I am working on for nextLine in inStream: logInConst += curLine curLine = nextLine # check if it is a start of a new log &amp;&amp; check if the previous log is 'ready' if newLogRegExp.match(curLine) and logInConst != "": counter = counter + 1 out = logInConst logInConst = "" yield out yield logInConst + curLine def checkFile (regExp, fileName): generatore = readLogs(fileName) listOfMatches=[] for i in generatore: #I'm now cycling through the logs # regExp must be a COMPILE regular expression if regExp.search(i): listOfMatches.append(i) return listOfMatches </code></pre> <p>in order to elaborate the info contained in those files. The function has the aim of write in just 1 line the logs that are stored in those files using 3 lines ... The function is working fine on files read from my local machine but I cannot figure out how to connect to a remote server and create these one-line logs without storing the content of each file into a string and then working with the string ... The command that I use to connect to the remote machine is :</p> <pre><code>connection_out = Popen(['ssh', retList[0], 'cd '+retList[2]+'; cat'+fileName], stdout=PIPE).communicate()[0] </code></pre> <p>retList[0] and retList[2] are the user@remote and the folder name that I have to access</p> <p>Thanks to all in advance !</p> <p><strong>UPDATE:</strong></p> <p>My problem is that I have to establish an ssh connection first :</p> <pre><code>pr1=Popen(['ssh', 'siatc@lgssp101', '*~/XYZ/AAAAA/log_archive/00/MSG_090308_162648.gz*' ], stdout=PIPE).communicate()[0] </code></pre> <p>All the files that I need to open are stored in a list, fileList[], part of them are compressed (.gz) and part are just text files !! I have tried all the procedures that u showed before bot nothing worked ... I think that I mus modify the third argument of the Popen function but I cannot figure out how to do it ! Is there anyone that can help me ???</p>
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