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PO"javax.crypto.BadPaddingException: Data must start with zero" exception
 

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  1. PO"javax.crypto.BadPaddingException: Data must start with zero" exception
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    <p>I encountered the abovementioned exception while I was decrypting a string.</p> <p>Below is my code:</p> <pre><code>import java.security.KeyPair; import java.security.KeyPairGenerator; import java.security.NoSuchAlgorithmException; import javax.crypto.Cipher; public class EncryptAndDecrypt { public static Cipher createCipher () throws Exception{ Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1Padding"); return cipher; } public static KeyPair generateKey () throws NoSuchAlgorithmException{ KeyPairGenerator keyGen = KeyPairGenerator.getInstance ("RSA"); keyGen.initialize(1024); KeyPair key = keyGen.generateKeyPair(); return key; } public static byte [] encrypt (String str, Cipher cip, KeyPair key) { byte [] cipherText = null; try { byte [] plainText = str.getBytes("UTF8"); cip.init(Cipher.ENCRYPT_MODE, key.getPublic()); cipherText = cip.doFinal(plainText); } catch (Exception e) { e.printStackTrace(); } return cipherText; } public static String decrypt (byte [] c, Cipher cip, KeyPair key) throws Exception { cip.init(Cipher.DECRYPT_MODE, key.getPrivate()); byte [] decryptedPlainText = cip.doFinal (c);// exception occurred here String decryptedPlainStr = new String (decryptedPlainText); return decryptedPlainStr; } } //separate class below to use the encrypt method public class EncryptionApp { public static void main (String [] args) { getEncrypted(); } public static byte [] getEncrypted () { byte [] encyptedByte = null; try { String plainText = "der"; Cipher cip = Safety.createCipher(); KeyPair key = Safety.generateKey(); encyptedByte = Safety.useRSA(plainText, cip, key); } catch (Exception e) { e.printStackTrace(); } return encyptedByte; } } // Another class to use the decrypt method public class DecryptionApp { public static void main(String[] args) { System.out.println (useDecrypted () ); } public static byte[] useDecrypted () { byte [] decryptedText = null; try { Cipher cip = EncryptAndDecrypt.createCipher(); KeyPair key = EncryptAndDecrypt.generateKey(); decryptedText = EncryptAndDecrypt.decrypt(EncryptionApp.getEncrypted(),cip,key); } catch (Exception e) { e.printStackTrace(); } return decryptedText; } } </code></pre>
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    1. CONobody will be able to help with your code if you don't show your code. Show us the exception stack trace as well, and indicate which line of the code is the line where the exception occurs.
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    2. COOk i will post my code. I was thinking that since someone posted before, it will be quite redundant if I posted it again.
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    3. COErm any idea on how to store the keypair inside a variable so that it will not change?
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