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    <p>One way would be to wrap the code want to run in a function and then have that function call your onSuccess code. Obviously this wrapped function would have to be returned from a function:</p> <pre><code>var checkDriftOnSuccess = function(onSuccess) { return function(transport) { var dateHeader = transport.getHeader('Date'); if (!dateHeader) { USER.serverDrift = 0; } else { USER.serverDrift = (new Date(dateHeader).getTime() - (new Date().getTime())) / 1000; } onSuccess(transport); }; }; </code></pre> <p>And you'd call it like this:</p> <pre><code>new Ajax.Request( 'someLink.php', { onSuccess: checkDriftOnSuccess(function(transport) { // application specific code here }) } ); </code></pre> <p><strong>UPDATE</strong>: another way, by replacing the Prototype constructor. Not favored by me (a) because I don't know the Prototype codebase, and (b) there may be <code>instanceOf</code> issues, and (c) I haven't actually tested it.</p> <pre><code>var ajaxReplacer = (function() { var oldRequest; var checkDriftOnSuccess = function(onSuccess) { return function(transport) { var dateHeader = transport.getHeader('Date'); if (!dateHeader) { USER.serverDrift = 0; } else { USER.serverDrift = (new Date(dateHeader).getTime() - (new Date().getTime())) / 1000; } onSuccess(transport); }; }; // save the real constructor oldRequest = Ajax.Request; // define a new constructor that wraps the onSuccess callback Ajax.Request = function(url, options) { if (options.onSuccess) { options.onSuccess = checkDriftOnSuccess(options.onSuccess); } // call the real constructor return new oldRequest(url, options); // alternately, call the real constructor using a function call // return oldRequest.call(this, url, options); }; Ajax.Request.prototype = oldRequest.prototype; return { reset: function() { Ajax.Request = oldRequest; } }; }()); </code></pre> <p>In essence it creates a new object called ajaxReplacer. This has one method, <code>reset</code> that returns everything to the default Prototype behavior (a one-shot deal). Creating the object will replace the ajax request constructor to one that calls the special code in <code>onSuccess</code>.</p> <p>Note I have two ways of calling the old code. I do not know which one will work properly since I don't use Prototype. Test, test, and test again. If it works, great. If it doesn't, maybe I forgot to do something, or it gives you enough ideas to really do it, or you just can't do this easily.</p>
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    1. COI was hoping for a a way where I don't have to change my hundreds of Ajax existing calls.
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    2. COOK, see the new code where I replace the Ajax.Request constructor. Personally speaking: I don't like this; I hate constructor functions.
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