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POThe opposite of string.Template in Python
 

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    <p>I know template can work like the following:</p> <pre><code>x = Template(" Coordinates; $o1;$o2;$o3;\n") y = x.substitute(o1 = 23, o2 = 108, o3 = 655) </code></pre> <p>and y will give me:</p> <pre><code>" Coordinates; 23;108;655;\n" </code></pre> <p>I am wondering if there is a way to do the reverse of this? something like my made up unpack:</p> <pre><code>x = Template(" Coordinates; $o1;$o2;$o3;\n") y = " Coordinates; 23;108;655;\n" z = x.unpack(y) </code></pre> <p>and have z return something like:</p> <pre><code>["23","108","655"] </code></pre> <p>any ideas? should i be using regular expressions instead?</p> <p><strong>EDIT:</strong> If using regular expressions how would i program for the following 3 lines to return the first number and the 6 trailing numbers?</p> <pre><code> a = " 123; Coord ; 19.1335; 3.5010; 1; 3; 8; 4" b = " 17; Coord ; 15.2940; 13.5010; 3; 1; 8; 8" c = " 5; Coord ; 19.1345; 0.6200; 1; 1; 7; 8" </code></pre> <p>I tried this on those and couldn't seem to get it working:</p> <pre><code>&gt;&gt;&gt; re.match('(\d+); Coord ;(\d+);(\d+);(\d+);(\d+);(\d+);(\d+)',a).groups() </code></pre> <p><strong>SOLUTION:</strong> Using regular expressions <a href="http://docs.python.org/howto/regex.html" rel="nofollow"><strong>tutorial</strong></a> (thanks ironchefpython):</p> <pre><code>&gt;&gt;&gt; import re &gt;&gt;&gt; text = """ 123; Coord ; 19.1335; 3.5010; 1; 3; 8; 4 17; Coord ; 15.2940; 13.5010; 3; 1; 8; 8 5; Coord ; 19.1345; 0.6200; 1; 1; 7; 8 """ &gt;&gt;&gt; coord = re.compile("\D*(\d+)\D+([\d\.]+)\D+([\d\.]+)\D+(\d+)\D+(\d+)\D+(\d+)\D+(\d+)") &gt;&gt;&gt; coord.findall(text) [('123','19.1335','3.5010','1','3','8','4'),('17','15.2940','13.5010','3','1','8','8'),('5','19.1345','0.6200','1','1','7','8')] </code></pre>
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