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    <p>First of all, why would you want that? I don't see any reason, or advantage:</p> <p>Anyway, you can do this:</p> <pre><code>template&lt;typename T&gt; int size(const std::vector&lt;T&gt; &amp;v) { return (int) v.size(); } //use std::vector&lt;int&gt; ints; //... int count = size(ints); </code></pre> <p>Still I don't see any point in doing that. You can simply write:</p> <pre><code>int count = (int) ints.size(); </code></pre> <p>But I would still say its not better than the following :</p> <pre><code>size_t count = ints.size(); //don't prefer anything over this. Always use size_t </code></pre> <h3>Advice: avoid using <code>int</code> for size. Prefer <code>size_t</code>.</h3> <hr> <p>As for the edit in your question. Why don't you use <code>size_t</code> as:</p> <pre><code>size_t something = 3; if(arr.size() &gt; something) </code></pre> <p>No warning. In my opinion, if you choose the data type consistently throughout your program, you wouldn't come across a situation when you've to compare <code>int</code> with <code>size_t</code> which is defined as <em>unsigned</em> integral type.</p> <p>Or if there is some legacy code which you've to work with, and which use <code>int</code> for size, then I think its better to use explicit cast when you need it, instead of adding a function in the framework itself, which hides the potential problem:</p> <pre><code>int something = /*some legacy code API call or something */; if(arr.size() &gt; (size_t) something) //or even better; size_t something = (size_t) /*some legacy code API call or something */; if(arr.size() &gt; something) </code></pre>
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    1. POHow to implement own function to std::vector?
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    1. COHow is it better than just casting? That's not what he asked for.
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    2. CO@littleadv I think it is exactly what he asked for: "a function that returns the .size() value as an integer"
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    3. CO@littleadv: Who said the function is better than casting? And why is even casting any better?
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