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    <p>For easy iterating over your nested dictionary, why not just write a simple generator?</p> <pre><code>def each_job(my_dict): for state, a in my_dict.items(): for county, b in a.items(): for job, value in b.items(): yield { 'state' : state, 'county' : county, 'job' : job, 'value' : value } </code></pre> <p>So then, if you have your compilicated nested dictionary, iterating over it becomes simple:</p> <pre><code>for r in each_job(my_dict): print "There are %d %s in %s, %s" % (r['value'], r['job'], r['county'], r['state']) </code></pre> <p>Obviously your generator can yield whatever format of data is useful to you.</p> <p>Why are you using try catch blocks to read the tree? It's easy enough (and probably safer) to query whether a key exists in a dict before trying to retrieve it. A function using guard clauses might look like this:</p> <pre><code>if not my_dict.has_key('new jersey'): return False nj_dict = my_dict['new jersey'] ... </code></pre> <p>Or, a perhaps somewhat verbose method, is to use the get method:</p> <pre><code>value = my_dict.get('new jersey', {}).get('middlesex county', {}).get('salesmen', 0) </code></pre> <p>But for a somewhat more succinct way, you might want to look at using a <a href="http://docs.python.org/library/collections.html#collections.defaultdict" rel="nofollow noreferrer">collections.defaultdict</a>, which is part of the standard library since python 2.5.</p> <pre><code>import collections def state_struct(): return collections.defaultdict(county_struct) def county_struct(): return collections.defaultdict(job_struct) def job_struct(): return 0 my_dict = collections.defaultdict(state_struct) print my_dict['new jersey']['middlesex county']['salesmen'] </code></pre> <p>I'm making assumptions about the meaning of your data structure here, but it should be easy to adjust for what you actually want to do.</p>
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