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    <p>You can't really do this, unless you're using C# 3.0 in which case you'll need to rely on LINQ (ehm, expression trees).</p> <p>What you do is that you create a dummy method for a lambda expression which lets the compiler generate the expression tree (compiler does the type checking). Then you dig into that tree to get the member. Like so:</p> <pre><code>static FieldInfo GetField&lt;TType, TMemberType&gt;( Expression&lt;Func&lt;TType, TMemberType&gt;&gt; accessor) { var member = accessor.Body as MemberExpression; if (member != null) { return member.Member as FieldInfo; } return null; // or throw exception... } </code></pre> <p>Given the following class:</p> <pre><code>class MyClass { public int a; } </code></pre> <p>You can get the meta data like this:</p> <pre><code>// get FieldInfo of member 'a' in class 'MyClass' var f = GetField((MyClass c) =&gt; c.a); </code></pre> <p>With a reference to that field you can then dig up any attribute the usual way. i.e. reflection.</p> <pre><code>static TAttribute GetAttribute&lt;TAttribute&gt;( this MemberInfo member ) where TAttribute: Attribute { return member.GetCustomAttributes( typeof( TAttribute ), false ) .Cast&lt;TAttribute&gt;().FirstOrDefault&lt;TAttribute&gt;(); } </code></pre> <p>Now you can dig up an attribute on any field by something which is in large checked by the compiler. It also works with refactoring, if you rename 'a' Visual Studio will catch that.</p> <pre><code>var attr = GetField((MyClass c) =&gt; c.a).GetAttribute&lt;DisplayNameAttribute&gt;(); Console.WriteLine(attr.DisplayName); </code></pre> <p>There's not a single literal string in that code there.</p>
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    1. COWow, thank you! This definitely works, I just tested it out. Very nice :)
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    2. CODon't forget to mark as answer ;)
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    3. COI think return member.Member as FieldInfo; should be return type of MemberInfo. Otherwise the casting always returns null.
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