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POQuartz HelloJob
 

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    <p>I am new to Quartz and I'm running into a compiling error. I am simply trying to get the HelloJob to run based on Quartz's Lesson 1 for Hello World. I am having trouble declaring a <code>JobDetail</code> with the error: <code>The method newJob(Class&lt;? extends Job&gt;)</code> in the type <code>JobBuilder</code> is not applicable for the arguments (Class)".</p> <p>Originally, the code had 3 errors at <code>newJob</code>, <code>newTrigger</code>, and <code>simpleSchedule</code> was </p> <pre><code>// define the job and tie it to our HelloJob class JobDetail job = newJob(HelloJob.class) .withIdentity("job1", "group1") .build(); // Trigger the job to run now, and then repeat every 40 seconds Trigger trigger = newTrigger() .withIdentity("trigger1", "group1") .startNow() .withSchedule(simpleSchedule() .withIntervalInSeconds(40) .repeatForever()) .build(); </code></pre> <p>without JobBuilder.newJob(...), TriggerBuilder.newTrigger(...), SimpleScheduleBuilder.simpleSchedule(...). Unlike the example given, I went ahead and added the imports and attached the class calls in front of newJob, newTrigger, etc. which got rid of 2/3 errors. But it seems the error persists with</p> <pre><code> JobDetail job = JobBuilder.newJob(HelloJob.class) .withIdentity("job1", "group1") .build(); </code></pre> <p>I have also tried replacing my job declaration with</p> <pre><code>JobDetail job = new JobDetail("job1", "group1", HelloJob.class); </code></pre> <p>but that ends with <code>Cannot instantiate the type JobDetail</code> and it seems like a few examples out there do this.</p> <p>Will really appreciate clarification,</p> <p>Thanks!</p>
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    1. USgturri
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    1. COcan u post the class "HelloJob"
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    2. COYeah, it was in my HelloJob not implementing Job. Sorry for making a silly mistake!
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    3. COThanks for asking this question; I had the same problem and it was great to find this solution. It seems a shame that the quartz documentation is a little buggy.
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      1. USRichard Corfield
 

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