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    <p><code>template&lt;&gt;</code> tells the compiler that a template specialization follows, specifically a <strong>full specialization</strong>. Normally, <code>class A</code> would have to look something like this:</p> <pre><code>template&lt;class T&gt; class A{ // general implementation }; template&lt;&gt; class A&lt;int&gt;{ // special implementation for ints }; </code></pre> <p>Now, whenever <code>A&lt;int&gt;</code> is used, the specialized version is used. You can also use it to specialize functions:</p> <pre><code>template&lt;class T&gt; void foo(T t){ // general } template&lt;&gt; void foo&lt;int&gt;(int i){ // for ints } // doesn't actually need the &lt;int&gt; // as the specialization can be deduced from the parameter type template&lt;&gt; void foo(int i){ // also valid } </code></pre> <p>Normally though, you shouldn't specialize functions, as <a href="http://www.gotw.ca/publications/mill17.htm">simple overloads are generally considered superior</a>:</p> <pre><code>void foo(int i){ // better } </code></pre> <hr> <p>And now, to make it overkill, the following is a <strong>partial specialization</strong>:</p> <pre><code>template&lt;class T1, class T2&gt; class B{ }; template&lt;class T1&gt; class B&lt;T1, int&gt;{ }; </code></pre> <p>Works the same way as a full specialization, just that the specialized version is used whenever the second template parameter is an <code>int</code> (e.g., <code>B&lt;bool,int&gt;</code>, <code>B&lt;YourType,int&gt;</code>, etc).</p>
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    1. POWhat is the meaning of template<> with empty angle brackets in C++?
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    1. CO+1 Good answer! Maybe you should add that this is a full template specialization. Even though.. with one template parameter, there's no partial specialization possible anyway.
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    2. COThis is also useful for defining type traits.
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    3. CO@Xeo: I wish downvoters would give a comment, anonymous or not (or at least the first of them).
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      1. USMatthieu M.
 

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