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    <p>I did something similiar to this in the past. You need to create a function that accepts an input string and a separator and returns a dataset. If separator is ommited, then comma is assumed.</p> <p>First create a new type that represents a table of strings:</p> <pre><code>create or replace type varcharTableType as table of varchar2(255); / </code></pre> <p>Then create this function:</p> <pre><code>create or replace function splitString( allValues in varchar2, delim in varchar2 default ',' ) return varcharTableType as str varchar2(255) := allValues || delim; pos number; dataset varcharTableType := varcharTableType(); begin loop pos := instr(str, delim); exit when (nvl(pos, 0) = 0); dataset.extend; dataset(dataset.count) := ltrim(rtrim(substr(str, 1, pos - 1))); str := substr(str, pos + length(delim)); end loop; return dataset; end; / </code></pre> <p>Finally, call as:</p> <pre><code>select * from table(cast(splitString('a,b,c') as varcharTableType)); COLUMN_VALUE --------------- a b c 3 rows selected </code></pre> <p>To answer your specific case, you simply need to create a view that joins your table with this function table, as: </p> <pre><code> create or replace view splitView as select yourTable.id, s.column_value as value from yourTable, table(cast(splitString(yourTable.value) as varcharTableType)) s; select * from splitView; id value ---- --------------- 1 a 1 b 1 c 3 rows selected </code></pre> <p>I am not sure if this last query will work, as I don't have an Oracle machine right now, but hopefully should help you.</p>
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