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  1. PO
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    <p>You can't overload operators for existing types, as that could potentially break any other code that uses the types.</p> <p>You can make your own class that encapsulates an array, expose the methods and properties that you need from the array, and overload any operators that makes sense.</p> <p>Example:</p> <pre><code>public class AddableArray&lt;T&gt; : IEnumerable&lt;T&gt; { private T[] _array; public AddableArray(int len) { _array = new T[len]; } public AddableArray(params T[] values) : this((IEnumerable&lt;T&gt;)values) {} public AddableArray(IEnumerable&lt;T&gt; values) { int len; if (values is ICollection&lt;T&gt;) { len = ((ICollection&lt;T&gt;)values).Count; } else { len = values.Count(); } _array = new T[len]; int pos = 0; foreach (T value in values) { _array[pos] = value; pos++; } } public int Length { get { return _array.Length; } } public T this[int index] { get { return _array[index]; } set { _array[index] = value; } } public static AddableArray&lt;T&gt; operator +(AddableArray&lt;T&gt; a1, AddableArray&lt;T&gt; a2) { int len1 = a1.Length; int len2 = a2.Length; AddableArray&lt;T&gt; result = new AddableArray&lt;T&gt;(len1 + len2); for (int i = 0; i &lt; len1; i++) { result[i] = a1[i]; } for (int i = 0; i &lt; len2; i++) { result[len1 + i] = a2[i]; } return result; } public IEnumerator&lt;T&gt; GetEnumerator() { foreach (T value in _array) { yield return value; } } IEnumerator System.Collections.IEnumerable.GetEnumerator() { return _array.GetEnumerator(); } } </code></pre> <p>Usage:</p> <pre><code>// create two arrays AddableArray&lt;int&gt; a1 = new AddableArray&lt;int&gt;(1, 2, 3); AddableArray&lt;int&gt; a2 = new AddableArray&lt;int&gt;(4, 5, 6); // add them AddableArray&lt;int&gt; result = a1 + a2; // display the result Console.WriteLine(string.Join(", ", result.Select(n=&gt;n.ToString()).ToArray())); </code></pre> <p>(Note that as the class implements <code>IEnumerable&lt;T&gt;</code>, you can use extension methods like <code>Select</code> on it.)</p>
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    1. USGuffa
    1. USGuffa
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      1. VTAcceptedByOriginator
    1. COThat's a lot code just so that a1 + a2 = unified array. Why not just do a1.Union(a2).ToArray()
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      1. USKeith
    2. COYes, that is a lot simpler, but it's not as efficient. It's fairly good though, a quick test shows that it only takes about 2-4 times longer.
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