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    <p>The most simple way to do what you want would be (I think):</p> <pre><code>$ = function(){ if (!(this instanceof $)){ return new $; } this.name = 'levi'; return this; } </code></pre> <p>The fact that just returning <code>this</code> doesn't create an instance of $ is because of the way <code>this</code> is created executing <code>$</code> as a regular function: in that case the value of <code>this</code> points to the global object (within a browser: <code>window</code>, actually calling executing <code>$()</code> is the same as <code>window.$()</code>). It's a fact of javascript life so to speak. The fact that <code>console.log(new $().name)</code> shows the right value is because you call the function as a constructor, which returns an instance of that constructor (i.e. an new instance of <code>$</code>). But <code>console.log($().name)</code> will also print 'levi', because it returns the global object with property <code>name</code>, i.e. <code>window.name</code>. try <code>$(); console.log(name)</code> and you'll see <code>name</code> is a global variable now. So if you don't want to use the <code>new</code> keyword every time, check if your function is called as a regular function, or as a constructor for an instance (<code>=== instanceof $</code>) within the constructor function. With the above method an instances constructor, no matter if it's instantiated with or without <code>new</code> will allways be <code>$</code></p> <p>Maybe you should rephrase the title of your question to: 'An Object [constructor] that returns <em>an instance of itself</em>'</p> <p>Maybe <a href="http://blog.tuenti.com/dev/functions-and-execution-contexts-in-javascript-2/" rel="nofollow">this blog entry</a> can shed extra light.</p>
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    1. POAn Object that returns an instance of itself
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    1. USKooiInc
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    1. POAn Object that returns an instance of itself
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    1. COYour code is "constructing" `this`, ie setting attributes, even when it returns a new instance. As for the rest, you are entirely correct.
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      1. USZecc
    2. CO@Zecc, you're right, the instanceof check should occur first. Code adapted.
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    3. COShame that you took so long. I accepted my own post that uses this technique because it didn't exist. **Edit:** Decided to delete own post to accept this one.
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      1. USLevi Morrison
 

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